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In how many ways can the digits in the number \(5,432,435\) be arranged?

Short Answer

Expert verified
The digits in the number 5,432,435 can be arranged in \( \frac{7!}{(2!)^2}\) different ways.

Step by step solution

01

Find the total number of permutations

The total permutations of a set are given by the formula \(n!\) where n is the number of elements in the set. In this case, the number has 7 digits, so the total number of permutations would be \(7!\)
02

Find the permutations of the repeated digits

Since digits 5 and 3 appear twice in the given number, compute how many times each of these numbers can be arranged within themselves. This would be \(2!\) for each digit. Therefore, the total permutations of the repeated digits would be \((2!)^2\).
03

Calculate the total different ways the digits can be arranged

Now, divide the total number of permutations which we found in Step 1, by the permutations of the repeated digits obtained in Step 2. That is, \( \frac{7!}{(2!)^2}\)

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