/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Use the formula for \({ }_{n} P_... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 11: Problem 41

Use the formula for \({ }_{n} P_{r}\) to evaluate each expression. \({ }_{6} P_{0}\)

Short Answer

Expert verified
The value of \(_6 P_0\) is 720.

Step by step solution

01

- Identify the values of n and r

From the permutation \(_6 P_0\), it can be seen that \(n=6\) and \(r=0\).
02

- Apply the permutation formula

The permutation formula is \(_n P_r = n! / (n - r)!\). By substituting the values of \(n\) and \(r\) into the permutation formula, it can be written as \(_6 P_0 = 6! / (6 - 0)!\).
03

- Calculate the factorial

The factorial of a non-negative integer \(n\) is the product of all positive integers less than or equal to \(n\). Here, the factorial of both 6 and 0 has to be calculated. It is given that \(6! = 6*5*4*3*2*1 = 720\) and \(0! = 1\) by definition.
04

- Substitute factorial values in formula

The values of \(6!\) and \(0!\) can be substituted back into the formula: \(_6 P_0 = 720/1\).
05

- Solve the expression

Upon carrying out the division, the result is \(_6 P_0 = 720\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain how to find and probabilities with dependent events. Give an example.

Write an original problem that can be solved using the Fundamental Counting Principle. Then solve the problem.

Write a probability problem involving the word "and" whose solution results in the probability fractions shown. \(\frac{1}{6} \cdot \frac{1}{6} \cdot \frac{1}{6}\)

Make Sense? Determine whether each statement makes sense or does not make sense, and explain your reasoning. My expected value in a state lottery game is \(\$ 7.50\).

Involve computing expected values in games of chance. The spinner on a wheel of fortune can land with an equal chance on any one of ten regions. Three regions are red, four are blue, two are yellow, and one is green. A player wins \(\$ 4\) if the spinner stops on red and \(\$ 2\) if it stops on green. The player loses \(\$ 2\) if it stops on blue and \(\$ 3\) if it stops on yellow. What is the expected value? What does this mean if the game is played ten times?
See all solutions

Recommended explanations on Math Textbooks

Discrete Mathematics

Read Explanation

Statistics

Read Explanation

Logic and Functions

Read Explanation

Probability and Statistics

Read Explanation

Geometry

Read Explanation

Mechanics Maths

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.