/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Use the formula for \({ }_{n} P_... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the formula for \({ }_{n} P_{r}\) to evaluate each expression. \({ }_{6} P_{0}\)

Short Answer

Expert verified
_{6} P_{0} = 1

Step by step solution

01

Substitute into the formula

First, substitute \(n = 6\) and \(r = 0\) into the formula \( _{n} P_{r} = \frac{n!}{(n-r)!}\). This gives \( _{6} P_{0} = \frac{6!}{(6-0)!}\).
02

Simplify the equation

Next, simplify the denominator of the fraction. Because \(6 - 0 = 6\), the equation is now \( _{6} P_{0} = \frac{6!}{6!}\).
03

Calculate the value

Finally, notice that the numerator and denominator are the same factorials, which results in \( _{6} P_{0} = 1\).

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