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Seven performers, \(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E}, \mathrm{F}\), and \(\mathrm{G}\), are to appear in a fund raiser. The order of performance is determined by random selection. Find the probability that a. D will perform first. b. E will perform sixth and B will perform last. c. They will perform in the following order: \(C, D, B, A, G\), \(\mathrm{F}, \mathrm{E}\). d. F or \(\mathrm{G}\) will perform first.

Short Answer

Expert verified
The probabilities are: a. \(\frac{1}{7}\), b. \(\frac{1}{42}\), c. \(\frac{1}{7!}\), d. \(\frac{2}{7}\).

Step by step solution

01

Probability that D will perform first

The probability that D will perform first is calculated by dividing 1 by the number of performers because each performer is equally likely to perform first. Hence, the probability is \(\frac{1}{7}\).
02

Probability of E performing sixth and B last

In this case, we have specified performers for the sixth and seventh spots. Therefore, the remaining five spots can be filled by any of the other performers in any order. This is a permutation of 5 performers, which results in \(5!\) different combinations. Considering the total number of combinations for seven performers, which is \(7!\), we find the probability by dividing \(5!\) by \(7!\), resulting in a probability of \(\frac{1}{7*6} = \frac{1}{42}\).
03

Probability of a defined order of performance

In this case, the order is fully defined. As there is only one way that this specific order can occur, the probability is \(\frac{1}{7!}\).
04

Probability that F or G will perform first

As each performer has an equal chance of performing first, and we now have two desired outcomes (F or G), we multiply the individual probability by 2, giving a result of \(\(\frac{2}{7}\)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutation and Combination
Understanding permutations and combinations is fundamental when calculating probabilities, especially in situations where order and selection play crucial roles. Permutation refers to the arrangement of objects in a specific order, which is important when the sequence is of importance, such as in a race or a queue. The number of permutations of n objects taken r at a time can be found using factorial notation, which brings us to the formula: P(n,r) = \( \frac{n!}{(n-r)!} \), where n! (n factorial) is the product of all positive integers up to n.
In contrast, combination considers the selection of objects without regard for the order they are arranged in. If you were picking a team or a committee, for example, the order in which members are chosen doesn't matter. Thus, the number of combinations of n objects taken r at a time is given by the formula: C(n,r) = \( \frac{n!}{r!(n-r)!} \). In our exercise, we encountered a permutation scenario when calculating the probability for E performing sixth and B last. It was a permutation because the order in which the other performers appeared was important. Using the permutation formula, we calculated the different possible lineups that adhered to the given conditions.
Factorial Notation
Factorial notation is an essential concept in probability and combinatorics. It is denoted by an exclamation point (!) and represents the product of all positive integers up to a given number. For instance, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\), and this operation is vital when calculating permutations and combinations.
When we mention \(7!\) in our exercise's solutions, it reflects the total number of unique ways in which 7 performers can be arranged. It is crucial when finding out probabilities in scenarios where each distinct arrangement, or permutation, represents a unique outcome. However, when some outcomes are fixed, like in the case of 'E performing sixth and B last', the total possible outcomes are reduced, which in turn impacts the probability. Factorial notation simplifies these calculations, making it easier to handle large numbers of combinations or permutations.
Sample Space in Probability
The concept of sample space is the cornerstone of probability theory. It is the set of all possible outcomes in a given experiment. In probability, the sample space is often denoted by the symbol \(S\). When trying to determine the probability of an event, it's imperative to consider the entire sample space because the probability is the ratio of the number of favorable outcomes to the number of all possible outcomes.
Take the last part of our exercise (part d), where we calculated the probability of either F or G performing first. The total sample space consists of seven possible outcomes (since there are seven performers, each with an equal chance of performing first), and the event we're interested in (F or G performing first) has two favorable outcomes. Therefore, by understanding the sample space, we can effectively determine the probability of events in various contexts. Without recognizing the full sample space, one might incorrectly calculate the chances of an event occurring.

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Most popular questions from this chapter

For a temporary job between semesters, you are painting the parking spaces for a new shopping mall with a letter of the alphabet and a single digit from 1 to 9 . The first parking space is \(\mathrm{A} 1\) and the last parking space is Z9. How many parking spaces can you paint with distinct labels?

A person can order a new car with a choice of six possible colors, with or without air conditioning, with or without automatic transmission, with or without power windows, and with or without a CD player. In how many different ways can a new car be ordered with regard to these options?

Are related to the SAT, described in Check Point 4 on page \(752 .\) A store specializing in mountain bikes is to open in one of two malls. If the first mall is selected, the store anticipates a yearly profit of \(\$ 300,000\) if successful and a yearly loss of \(\$ 100,000\) otherwise. The probability of success is \(\frac{1}{2}\). If the second mall is selected, it is estimated that the yearly profit will be \(\$ 200,000\) if successful; otherwise, the annual loss will be \(\$ 60,000\). The probability of success at the second mall is \(\frac{3}{4}\). Which mall should be chosen in order to maximize the expected profit?

In how many ways can a casting director choose a female lead and a male lead from five female actors and six male actors?

Are related to the SAT, described in Check Point 4 on page \(752 .\) An oil company is considering two sites on which to drill, described as follows: Site A: Profit if oil is found: \(\$ 80\) million Loss if no oil is found: \(\$ 10\) million Probability of finding oil: \(0.2\) Site B: Profit if oil is found: \(\$ 120\) million Loss if no oil is found: \(\$ 18\) million Probability of finding oil: \(0.1\) Which site has the larger expected profit? By how much?

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