91Ó°ÊÓ

First, identify the total number of people in the sample space. This includes 8 male professors, 11 female professors, 14 male teaching assistants, and 7 female teaching assistants. The total is \(8+11+14+7 = 40\).

Next, calculate the probability of selecting a professor. There are 8 male and 11 female professors, making the total number of professors \(8+11 = 19\). The probability of selecting a professor is then given by the ratio of the number of professors to the total number of people: \(P(\text{Professor}) = \frac{19}{40}\).

Next, calculate the probability of selecting a female. There are 11 female professors and 7 female teaching assistants, making the total number of females \(11+7 = 18\). The probability of selecting a female is thus \(P(\text{Female}) = \frac{18}{40}\).

Finally, calculate the combined probability of selecting a person who is either a professor or a female. Bear in mind that these two events are not mutually exclusive (a female professor is both a professor and a female). Therefore, the formula to calculate the probability of either of two non mutually exclusive events is \(P(A or B) = P(A) + P(B) - P(A and B)\), where A is selecting a professor and B is selecting a female. Here, \(P(A and B)\) is the probability of selecting a female professor, which is \(\frac{11}{40}\). By applying the formula, we get \(P(\text{Professor or Female}) = P(\text{Professor}) + P(\text{Female}) - P(\text{Female Professor}) =\frac{19}{40}+\frac{18}{40}-\frac{11}{40} =\frac{26}{40}= 0.65\).