/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Evaluate each factorial expressi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate each factorial expression. \(\frac{19 !}{11 !}\)

Short Answer

Expert verified
The value of \(\frac{19 !}{11 !}\) is the product of the numbers between 19 to 12, which equals to 3,715,891,200.

Step by step solution

01

Understanding Factorials

Express both the factorials in their expanded form. So, basically we are writing the factorials as product of numbers: \(19! = 19*18*17*...*2*1\) and \(11! = 11*10*9*...*2*1\).
02

Simplifying the Expression

Since 19! can be expressed as \(19*18*17*...*2*1\) and 11! as \(11*10*9*...*2*1\), the term \(\frac{19 !}{11 !}\) can be simplified to \(\frac{19*18*17*16*15*14*13*12*11*10*9*...*2*1}{11*10*9*...*2*1}\). Here, the denominator is common to the numerator, hence, we can cancel out the common terms.
03

Final Simplification

After cancelling out the common parts in the numerator and denominator, we are left with \(19*18*17*16*15*14*13*12\). Now calculate the product of these numbers to get the final answer.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How many four-digit odd numbers are there? Assume that the digit on the left cannot be 0 .

As in Exercise 1, six performers are to present their comedy acts on a weekend evening at a comedy club. One of the performers insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different ways are there to schedule the appearances?

In the original plan for area codes in 1945 , the first digit could be any number from 2 through 9 , the second digit was either 0 or 1 , and the third digit could be any number except 0 . With this plan, how many different area codes are possible?

Make Sense? Determine whether each statement makes sense or does not make sense, and explain your reasoning. An apartment complex offers apartments with four different options, designated by A through D. There are an equal number of apartments with each combination of options. $$ \begin{array}{|l|l|l|l|} \hline \text { A } & \text { B } & \text { C } & \text { D } \\ \hline \text { one bedroom } & \text { one } & \text { first } & \text { lake view } \\ \text { two bedrooms } & \text { bathroom } & \text { floor } & \text { golf course } \\ \text { three } & \text { two } & \text { second } & \text { view } \\ \text { bedrooms } & \text { bathrooms } & \text { floor } & \text { no special } \\ & & & \text { view } \\ \hline \end{array} $$ If there is only one apartment left, what is the probability that it is precisely what a person is looking for, namely two bedrooms, two bathrooms, first floor, and a lake or golf course view?

A camp counselor and six campers are to be seated along a picnic bench. In how many ways can this be done if the counselor must be seated in the middle and a camper who has a tendency to engage in food fights must sit to the counselor's immediate left?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.