/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 From the top of a 250 -foot ligh... [FREE SOLUTION] | 91Ó°ÊÓ

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From the top of a 250 -foot lighthouse, a plane is sighted overhead and a ship is observed directly below the plane. The angle of elevation of the plane is \(22^{\circ}\) and the angle of depression of the ship is \(35^{\circ}\). Find a. the distance of the ship from the lighthouse; b. the plane's height above the water. Round to the nearest foot.

Short Answer

Expert verified
a. The distance of the ship from the lighthouse is approximately 366ft. b. The total height of the plane from the water is approximately 1043ft.

Step by step solution

01

Establish the Scenario

First Identify all given information and visualize the scenario. From the top of a lighthouse, two right triangles can be formed using the line of sight to the plane and the ship. The angle of elevation to the plane is \(22^{\circ}\) and the angle of depression to the ship is \(35^{\circ}\). This means that the angle of depression to the plane from the horizontal is \(90^{\circ}-22^{\circ}=68^{\circ}\). Since depression and elevation are opposite, they are equal, so the angle of elevation from the ship to the plane is also \(68^{\circ}\). Thus, the lighthouse, the ship, and the plane form a straight line.
02

Calculate the Distance of the Ship from the Lighthouse

In the triangle formed by the lighthouse, ground, and the ship, which we know is a right triangle, we can use tangent of the angle, which is the ratio of the opposite side to the adjacent side. The formula is \(\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\). Applying the formula, we get \(\tan(35^{\circ}) = \frac{250\text{ft}}{\text{distance}}\). Solving this for the distance, we find that the distance of the ship from the lighthouse is approximately \(366\text{ft}\).
03

Calculate the Plane's Height Above the Water

In the triangle formed by the plane, the lighthouse, and the point directly underneath the plane on the ground, we again use the tangent of the angle. Thus, we have \(\tan(68^{\circ}) = \frac{\text{height}}{366\text{ft}}\). Solving this for the height, we find that the plane's height above the water is roughly \(793\text{ft}\). Adding the height of the lighthouse to this, we get that the total height of the plane from the water is \(793\text{ft} + 250\text{ft} = 1043\text{ft}\).

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