/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 87. Powerful potatoes Refer to Exerc... [FREE SOLUTION] | 91影视

91影视

Powerful potatoes Refer to Exercise 85. Determine if each of the following

changes would increase or decrease the power of the test. Explain your answers.

a. Change the significance level to =0.10

b. Take a random sample of 250 potatoes instead of 500 potatoes.

c. The true proportion is p=0.10 instead of p=0.11

Short Answer

Expert verified

Part (a) Power increases.

Part (b) Power decrease.

Part (c) Power decrease.

Step by step solution

01

Part (a) Step 1: Given information

Hypothesized population proportion (p0)=0.08

Sample size (n)=500

Level of significance ()=0.05

Power = 0.764

H0:p=0.08Ha:p>0.08
02

Part (a) Step 2: Explanation

When the alternative hypothesis is true, the power is the probability of rejecting the null hypothesis. Increasing the significance threshold from =0.05to=0.10is a good way to start. Because the significance level measures the likelihood of making a type I error, as the significance level rises, the likelihood of making a type I error rises, and the likelihood of making a type II error decreases. As a result, the probability of a type II error reduces the power by one, and the power grows.

03

Part (b) Step 1: Explanation

When the alternative hypothesis is true, the power is the probability of rejecting the null hypothesis. The sample size was reduced from 500to 250

Because the sample size has been reduced, there is less knowledge of the population, resulting in less reliable estimates. Because our estimations are less accurate, we are less likely to reject the null hypothesis correctly (once the alternative hypothesis is true), lowering our power.

04

Part (c) Step 1: Explanation

When the alternative hypothesis is true, the power is the probability of rejecting the null hypothesis. By changing the true proportion to p=0.10instead of p=0.11the proportion is closer to the hypothesized proportion of 0.08 Because the difference between the true and hypothesized proportions is less, detecting that the hypothesized proportion is not the true proportion will be more difficult, and hence the power will be reduced.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Potato chips A company that makes potato chips requires each shipment of

potatoes to meet certain quality standards. If the company finds convincing evidence that more than 8%of the potatoes in the shipment have 鈥渂lemishes,鈥 the truck will be sent back to the supplier to get another load of potatoes. Otherwise, the entire truckload will be used to make potato chips. To make the decision, a supervisor will inspect a random sample of potatoes from the shipment. He will then perform a test of H0:p=0.08versus Ha:p>0.08, where p is the true proportion of potatoes with blemishes in a given truckload. The power of the test to detect that p=0.11, based on a random sample of 500 potatoes and significance level =0.05, is 0.764Interpret this value.

Watching grass grow The germination rate of seeds is defined as the proportion of seeds that sprout and grow when properly planted and watered. A certain variety of grass seed usually has a germination rate of 0.80. A company wants to see if spraying the seeds with a chemical that is known to increase germination rates in other species will increase the germination rate of this variety of grass. The company researchers spray a random sample of 400grass seeds with the chemical, and 339of the seeds germinate. Do these data provide convincing evidence at the =0.05 significance level that the chemical is

effective for this variety of grass?

Losing weight A Gallup poll found that 59% of the people in its sample said 鈥淵es鈥 when asked, 鈥淲ould you like to lose weight?鈥 Gallup announced: 鈥淔or results based on the total sample of national adults, one can say with 95% confidence that the margin of (sampling) error is 卤3 3percentage points.鈥12 Based on the confidence interval, is there convincing evidence that the true proportion of U.S. adults who would say they want to lose weight differs from 0.55? Explain your reasoning

Which of the following 95%confidence intervals would lead us to reject H0:p=0.30in favor of Ha:pnotequalto0.30at the 5%significance level?

a. (0.19,0.27)

b.(0.24,0.30)

c. (0.27,0.31)

d. (0.29,0.31)

e. None of these

Water! A blogger claims that U.S. adults drink an average of five 8-ounce glasses (that鈥檚 40 ounces) of water per day. Researchers wonder if this claim is true, so they ask a random sample of 24 U.S. adults about their daily water intake. A graph of the data shows a roughly symmetric shape with no outliers.

a. State an appropriate pair of hypotheses for a significance test in this setting. Be sure to define the parameter of interest.

b. Check conditions for performing the test in part (a).

c. The 90% confidence interval for the mean daily water intake is 30.35 to 36.92 ounces. Based on this interval, what conclusion would you make for a test of the hypotheses in part (a) at the 10% significance level?

d. Do we have convincing evidence that the amount of water U.S. children drink per day differs from 40 ounces? Justify your answer.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.