91Ó°ÊÓ

Claim is that the mean is $40$ ounces.

The null hypothesis asserts that the population value is the same as the claim value:

$H_0:\mathrm{μ}=40$

Either the null hypothesis or the alternative hypothesis is the assertion. The null hypothesis asserts that the population means is the same as the claim value. If the claim is the null hypothesis, the alternative hypothesis statement is the polar opposite of the claim.

$H_1:\mathrm{μ}≠40$

$\mathrm{μ}$is the mean daily water intake of U.S. adults.

The three conditions are Random, independent, and Normal/ Large sample.

Random: Because the sample is a random sample, I'm satisfied.

Independent: Because the sample of $24$ individuals in the United States represents less than $10\%$ of the total adult population in the United States, I am happy.

Normal/Large sample: Satisfied since the data graph reveals no outliers or skewed distribution. Because all of the prerequisites are met, a hypothesis test for the population mean is appropriate.

$90\%$ confidence interval:

$(30.35,36.92)$

A hypothesis test with a significance level of $100\%-90\%=10\%$ is associated with a $90\%$ confidence interval.

It is noted that the confidence interval does not include $40$ implying that the mean daily water consumption is unlikely to be $40$ ounces, and so there is convincing proof that the mean daily water intake is not $40$ ounces.

Because the data is based on adults in the United States, it is impossible to conclude that children in the United States have a different daily water intake than adults.

It signifies that we don't have enough data to believe that the average daily water intake of American youngsters is less than $40$ ounces.