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Each wheel has five symbols.

Each of the five symbols has an equal chance of appearing, therefore four and five symbols are not apples.

The probability is,

$P(no.ofapple)=\frac{favourableoutcomes}{possibleoutcomes}=\frac{4}{5}=0.8$

The multiplication rule says that

$P(AandB)=P\left(A\right)脳P\left(B\right)$

Using the multiplication rule, determine the probability of getting no. apples on five wheels:

$$\begin{gathered} P(5no.ofapples)=P(noapple)脳...脳P(noapple)={P(noapple)}^5 \\ ={0.85}^5=0.32768 \end{gathered}$$

Using the complement rule, calculate the likelihood of getting at least one apple on five wheels:

$$\begin{gathered} P(notA=1鈭�P(A)P(atleast1appleon5wheels) \\ =1鈭�P(5noapples) \\ =1鈭�0.32768 \\ =0.67232 \end{gathered}$$

The odds of a slot player getting at least one apple in a single pull of the lever are $0.67232$to$1$

Each of the five symbols has an equal chance of appearing, therefore four and five symbols are not apples.

The probability is,

$P(no.ofapple)=\frac{favourableoutcomes}{possibleoutcomes}=\frac{4}{5}=0.8$

According to the rule of multiplication,

$P(AandB)=P\left(A\right)脳P\left(B\right)$

Using the multiplication rule, determine the probability of getting no. apples on five wheels:

$$\begin{gathered} P(5no.ofapples)=P(noapple)脳...脳P(noapple)={P(noapple)}^5 \\ ={0.8}^5=0.32768 \end{gathered}$$

Using the complement rule, calculate the likelihood of getting at least one apple on five wheels:

$P(notA=1鈭�P(A)$

After that, the final answer is calculated.

Reader鈥檚 answer is $0.996222$