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Chapter 6: Q. 78 (page 358)

Long or short? Put the names of all the students in your statistics class in a hat. Mix up the names, and draw 4 without looking. Let X = the number whose last names have more than six letters.

Short Answer

Expert verified

The given statement is correct, is based on the binomial distribution.

Step by step solution

01

Given Information

The Trials is conductedn=4

X = the number whose last names have more than six letters.

02

According to the given question

The random variable X satisfies the following requirements.

1. There is no indication of the likelihood of success. As a result, it isn't corrected.

2. The number of names is set.

3. The names on the slips are not unrelated to one another.

4. There are two possibilities.

All of the binomial criteria are not met in this case.

As a result, X can be considered to follow the binomial distribution.

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Most popular questions from this chapter

Toothpaste Ken is traveling for his business. He has a new 0.85-ounce tube of toothpaste that鈥檚 supposed to last him the whole trip. The amount of toothpaste Ken squeezes out of the tube each time he brushes is independent, and can be modeled by a Normal distribution with mean 0.13 ounce and standard deviation 0.02 ounce. If Ken brushes his teeth six times on a randomly selected trip, what鈥檚 the probability that he鈥檒l use all the toothpaste in the tube?

Easy-start mower Refer to Exercise 92 .

a. Calculate and interpret the mean of T.

b. Calculate and interpret the standard deviation of T.

1-in-6 wins Alan decides to use a different strategy for the 1-in-6 wins game of Exercise 90炉. He keeps buying one 20 -ounce bottle of the soda at a time until he gets a winner.

a. Find the probability that he buys exactly 5 bottles.

b. Find the probability that he buys at most 6 bottles. Show your work.

In which of the following situations would it be appropriate to use a Normal distribution to approximate probabilities for a binomial distribution with the given values of n and p ?

a. n=10,p=0.5

b. n=40,p=0.88

c. n=100,p=0.2

d. n=100,p=0.99

e.n=1000,p=0.003

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