91影视

Given,

Used concept:

If the sample size or number of trials is n and the success probability is p.

Both of the following conditions must be met for the binomial distribution to be regularly approximated.

$$\begin{gathered} n脳p>5 \\ n脳(1-p)>5 \end{gathered}$$

Lets Check the following condition

$$\begin{gathered} \mathrm{n}脳\mathrm{p}=10脳0.5=5 \\ \mathrm{n}脳1-\mathrm{p}=10脳1-0.5=5 \end{gathered}$$

Because both assumptions are not met in this case, typical approximation is not acceptable.

Given,

Lets Check the following condition

$$\begin{gathered} \mathrm{n}脳\mathrm{p}=40脳0.88=35.2 \\ \mathrm{n}脳1-\mathrm{p}=10脳1-0.88=4.8 \end{gathered}$$

Because the first requirement is met but the second is not, normal approximation is not appropriate.

Given,

Lets Check the following condition

$$\begin{gathered} \mathrm{n}脳\mathrm{p}=100脳0.2=20 \\ \mathrm{n}脳1-\mathrm{p}=100脳1-0.2=80 \end{gathered}$$

Because both prerequisites are met in this case, conventional approximation is appropriate.

Given,

Lets Check the following condition

$$\begin{gathered} \mathrm{n}脳\mathrm{p}=100脳0.99=99 \\ \mathrm{n}脳1-\mathrm{p}=100脳1-0.99=1 \end{gathered}$$

Because the first criterion is satisfied but the second is not, normal approximation is not appropriate.

Given,

Lets Check the following condition

$$\begin{gathered} \mathrm{n}脳\mathrm{p}=1000脳0.003=3 \\ \mathrm{n}脳1-\mathrm{p}=1000脳1-0.003=997 \end{gathered}$$

Because the second criteria is met but the first is not, normal approximation is not applicable.