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Toothpaste Ken is traveling for his business. He has a new 0.85-ounce tube of toothpaste that鈥檚 supposed to last him the whole trip. The amount of toothpaste Ken squeezes out of the tube each time he brushes is independent, and can be modeled by a Normal distribution with mean 0.13 ounce and standard deviation 0.02 ounce. If Ken brushes his teeth six times on a randomly selected trip, what鈥檚 the probability that he鈥檒l use all the toothpaste in the tube?

Short Answer

Expert verified

Ken's chances of finishing the tube of toothpaste are 0.0764.

Step by step solution

01

Given information

The value of the mean

X=0.13ounce

The value of standard deviation,

X=0.02ounce

The value of Tube weighs,

x=0.85-ounce

02

Calculation

If X and Y are independent,

The Property mean:

aX+bY=aX+bY

The Property variance:

aX+bY2=a2X2+b2Y2

Now,

Brushing six times' mean is the sum of brushing six times' mean:

X1+X2+X3+X4+X5+X6=X1+X2+X3+X4++X3+X6=6X=6(0.13)=0.78ounce

We know that

The square root of variance is standard deviation:

X1+X2+X3+X4+X5+X6=X12+X22+X32+X42+X52+X62=6(0.02)20.0490ounce

Find the z - score:

z=x-=0.85-0.780.04901.43

To find the relevant probability, use Table - A:

P(X>0.85)=&P(z>1.43)=1-P(z<1.43)=1-0.9236=0.0764

Thus,

Ken's chances of using the entire tube of toothpaste are little to none 0.0764.

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