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We are given different of different kind of vehicles and their probability of being chosen . We need to find the probability of crossover vehicle.

Total probability of an event to completely occur is equal to $1$.

Probability of all vehicles$=1$

Let probability of choosing crossover be$x$.

$0.46+0.15+0.10+x+0.05=1$

$0.76+x=1$

$x=0.24$

Probability of choosing crossover vehicle is$0.24$.

We are given different of different kind of vehicles and their probability of being chosen . We need to find the probability that vehicle is not an SUV or Minivan .

Probability of an event to completely occur is equal to $1$.

Probability ( Vehicle is not an SUV or Minivan) $=1-$(Probability of choosing SUV $+$Probability of choosing Minivan).

Probability ( vehicle is not an SUV or Minivan) $$\begin{gathered} =1-(0.10+0.05) \\ =1-0.15 \\ =0.85 \end{gathered}$$

We are given different of different kind of vehicles and their probability of being chosen . We need to find that if vehicle is not a passenger car, what is the probability that it is a pickup truck .

The probability if vehicle is not a passenger car, but is a pickup truck is given in the problem itself and is equal to $0.15$