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We are given three different vehicles and if a person exercises or not . We need to find if the person drives an SUV .

We need to find the total and divide favorable outcome by total outcomes in order to achieve the probability .

So, probability (person drives an SUV ) $=\frac{39}{120}$

$=0.325$

We are given three different vehicles and if a person exercises or not . We need to find the probability that the person drives a sedan or exercises for at least 30 minutes four or more times per week.

We need to add probability of both the cases .

Probability (person drives a sedan or exercises for at least 30 minutes four or more times per week)$=$Probability (person drives a sedan) $+$Probability (sedan in total ) $-$Probability (yes in exercise)

Required probability$$\begin{gathered} =\frac{45}{120}+\frac{52}{120}-\frac{25}{120} \\ =\frac{72}{120} \\ =0.6 \end{gathered}$$

We are given different vehicles and if a person exercises or not. We need to find the probability that the person does not drive a truck, given that she or he exercises for at least 30 minutes four or more times per week .

Required Probability$=$$$\begin{gathered} \frac{25}{120}+\frac{15}{120} \\ =\frac{40}{120} \\ =0.33 \end{gathered}$$