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We are given the values of probability of household own dog and household own cat and those who own both and we have to make a Venn diagram to show the probability of household own either cat or dog.

According to the question,

The probability of a household having a dog is$0.40$, probability of a household having a cat is$32\%$and those who have both is$18\%$.

A Venn diagram showing the probability of having a dog or cat

Here,$46\%$is showing the household having either cat or dog.

We are given the values of the probabilities of a household's own dog, a household's owning a cat, and those who own both and we have to find out the value of$P(D鈭�C^C)$.

To find out the value of the given probability, we required the probability of a household owning a dog, which is,$0.40-0.18=0.22$and the probability of a household now owning a cat, which is,$1-0.32=0.68$and the probability of a household having a dog or not having a cat, islocalid="1654001282795" $0.22+0.46=0.68$.

Now, apply the union rule of probability,

which is$P\left(A鈭�B\right)=P\left(A\right)+P\left(B\right)+P(A鈭�B)$

We get,$P\left(D鈭�C^C\right)=0.22+0.68-0.68=0.22$.