91影视

We are given the values of those who are republicans and those who are female democrats and those who are male and republicans both, and we have to find the probability of those who are either republicans or male.

Applying the union rule of probability

which is$P\left(A鈭�B\right)=P\left(A\right)+P\left(B\right)+P(A鈭�B)$,

Here, P (R)$=0.52$, P (M)$=1-P\left(F\right)=1-0.21=0.79$and P$\left(R鈭�M\right)=0.47$

Put all the values in the rule.

We get $P\left(R鈭�M\right)=0.52+0.79-0.47=0.84$

Hence, the probability of those who are republican or male is$0.84$.

We are given the values of those who are republicans and those who are female democrats and those who are male and republican both, and we have to find out the probability of those who are female or independent.

Applying the union rule of probability,

which is$P\left(A鈭�B\right)=P\left(A\right)+P\left(B\right)+P(A鈭�B)$

Here, the probability of students who are female or independent is denoted by$P\left(F鈭�I\right)$. Now, to find its value,

P(F)$=0.21$, P(I)$=1-P\left(R\right)=1-0.52=0.48$

and P$(F鈭�I)=0.53$

Put all the values in the union rules.

We get$P(F鈭�I)=0.21+0.48-0.53=0.16$.

Hence, the probability is$0.16$.