91影视

We are given the values of the students who are undergraduate and who use Macs and also those who are both graduate and use Macs, and we have to find out the probability of those who are either graduate or use Macs.

Applying the union rule of probability

which is$P\left(A鈭�B\right)=P\left(A\right)+P\left(B\right)+P(A鈭�B)$,

Here, P (G)$=1-P\left(U\right)=1-0.67=0.33$, P (M)$=0.60$and $P(G鈭�M)=0.23$

Put all the values in the rule.

We get $P\left(G鈭�M\right)=0.33+0.60-0.23=0.70$

Hence, the probability of those who are graduates or using Macs is$0.70$

We are given the values of the students who are undergraduate and who use Macs and also those who are both graduate and use Macs, and we have to find out the probability of those who are graduate or use Macs.

Applying the union rule of probability,

which is$P\left(A鈭�B\right)=P\left(A\right)+P\left(B\right)+P(A鈭�B)$

Here, the probability of students who are undergraduates and use primarily PCS is denoted by $P\left(U鈭�P\right)$. Now, to find its value,

P(U)$=0.67$, P(P)$=1-P\left(M\right)=1-0.60=0.40$

and P$(U鈭�P)=1-0.23=0.77$

Put all the values in the union rules.

we get$P\left(U鈭�P\right)=0.67+0.40-0.77=0.30$.

Hence, the probability is$0.30$.