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We have to describe how you would use slips of paper device to perform one trial of the simulation.

鈥冣赌�$$\begin{gathered} 0.60=\frac{60}{100} \\ =\frac{3}{5} \end{gathered}$$

Now we will write numbers $1,2,3,4$and $5$each on different slips of papers. And then,

鈥�$鈥�1,2,3$=Hit centre $4,5$=Do not hit centre

We have to describe how you would use random digit table device to perform one trial of the simulation.

In the question there is a certain archery competition and there is a $0.60$probability of hitting the centre of the largest on each shot which corresponds with about $3$out of every $5$shots. As,

$$\begin{gathered} 0.60=\frac{60}{100} \\ =\frac{3}{5} \end{gathered}$$

We have to describe how you would use random number generator device to perform one trial of the simulation.

In the question there is a certain archery competition and there is a $0.60$probability of hitting the centre of the largest on each shot which corresponds with about $3$out of every $5$ shots. As,

$$\begin{gathered} 0.60=\frac{60}{100} \\ =\frac{3}{5} \end{gathered}$$

Now we will consider numbers$1,2,3,4$and $5$such that:

鈥�$鈥�1,2,3$=Hit centre $4,5$=Do not hit centre

Now, we enter the following command into your $Ti83/Ti84$calculator, which will simulate $20$shots as:

鈥冣赌�$randInt(1,5,20)$

where $randInt$can be found in the MATH menu under PRB. Thus, count the number of digits you need until you obtain two-digits that are $4$or $5$which thus represents the number of trials needed to miss the centre twice.