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Acing the GRE The Graduate Record Examinations (GREs) are widely used to help predict the performance of applicants to graduate schools. The scores on the GRE Chemistry test are approximately Normal with a mean = of 694 and a standard deviation =112

a. Approximately what percent of test-takers earn a score less than 500 or greater than 900 on the GRE Chemistry test?

b. Estimate the 99th percentile score on the GRE Chemistry Test.

Short Answer

Expert verified

Part (a) The percentage is 7.47%

Part (b) The percentile is 954.96

Step by step solution

01

Part (a) Step 1: Given information

Population mean (μ)=694

Standard deviation (σ)=112

02

Part (a) Step 2: Calculation 

The random variable X displays the earning score according to the normal distribution.

The percentage of tests with scores of less than 500 or more than 900 can be computed as follows:

P(X<500orX>900)=P(x−μσ<500−μσ)+P(x−μσ>900−μσ)=P(Z<500−694112)+P(Z>900−694112)=P(Z<−1.73)+P(Z>1.84)=0.0747

Thus, the required percentage is 7.47%

03

Part (b) Step 1: Calculation

The z-score for the probability of 0.99 is 2.33 using the usual normal table.

The test's 99thpercentile can be determined as follows:

x=μ+Z×σ=694+(2.33)×112=954.96

Therefore, the required percentile is 954.96

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