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Standard Normal areas Find the proportion of observations in a standard Normal distribution that satisfies each of the following statements.

a. z>1.66

b.1.66<z<2.85

Short Answer

Expert verified

Part (a) Around 0.9515of the observations in a standard Normal distribution satisfy the statement.

Part (b) Around 0.9493 of the observations in a standard Normal distribution satisfy the statement.

Step by step solution

01

Part (a) Step 1: Given information

z>1.66

02

Part (a) Step 2: Concept

The formula used: Use the complement ruleP(notA)=1P(A)

03

Part (a) Step 3: Calculation

To find the equivalent probability, use the normal probability table in the appendix.

In the typical normal probability table for P(z<1.66)look at the row that starts with-1.6 and the column that starts with.06

Then

Use the complement rule,

P(notA)=1P(A)

For probability

P(z>1.66)P(z>1.66)=1P(z<1.66)=10.0485=0.9515

Therefore,

Around 0.9515 of the observations in a standard Normal distribution satisfyz>1.66

04

Part (b) Step 1: Given information

1.66<z<2.85

05

Part (b) Step 2: Calculation

To find the equivalent probability, use the normal probability table in the appendix.

In the typical normal probability table for P(z<1.66)look at the row that starts with -1.6and the column that starts with.06

And

The usual normal probability table for P(z<2.85)has a row that starts with 2.8and a column that starts with.05

Then

P(1.66<z<2.85)=P(z<2.85)P(z<1.66)=0.99780.0485=0.9493

Therefore,

Around 0.9493of the observations in a standard Normal distribution satisfy 1.66<z<2.85

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