91影视

The relationship between the height and age of the students is given in the question. And the regression line is as:

$\stackrel{铃�}{y}=106.1+4.21x$

And also given that the student was $141cm$tall at age $10$Thus, we have,

$$\begin{gathered} x=10 \\ y=141 \end{gathered}$$

Thus the predicted height of the student is as:

$\stackrel{铃�}{y}=106.1+4.21x$

$$\begin{gathered} =106.1+4.21\left(10\right) \\ =148.2 \end{gathered}$$

Thus, the residual will be calculated as:

$$\begin{gathered} Residual=y鈭�\stackrel{铃�}{y} \\ =141鈭�148.2 \\ =鈭�7.2 \end{gathered}$$

This means that while using the regression line to make a prediction, we overestimated the height of the student at age $10$ by $7.2cm$

The question specifies the relationship between the students' height and age. The regression line is as follows:

$\stackrel{铃�}{y}=106.1+4.21x$

Also, at the age of ten, the pupil was $141$ cm tall. As a result,

$$\begin{gathered} x=10 \\ y=141 \end{gathered}$$

The slope in the least square regression equation is the coefficient of $x$, and it indicates the average rise or decrease of $y$ per unit of $x$ Thus,

$b_1=4.21$

As a result, the height increases by $4.21$ cm per year on average.

The question specifies the relationship between the students' height and age. The regression line is as follows:

$\stackrel{铃�}{y}=106.1+4.21x$

Also, at the age of ten, the pupil was 141 cm tall. As a result,

$$\begin{gathered} x=10 \\ y=141 \end{gathered}$$

$s=8.61$ is the value of s. The standard error of the estimations, as we all know, is the average error of forecasts, and thus the average difference between actual and predicted values. Thus, using the equation of least square regression line deviation, a student's anticipated height differs by $8.61cm$from his or her actual height.

The question specifies the relationship between the students' height and age. The regression line is as follows:

$\stackrel{铃�}{y}=106.1+4.21x$

Also, we have, given that the pupil was $141$ cm tall at the age of ten,

$$\begin{gathered} x=10 \\ y=141 \end{gathered}$$

And the value of $r^2$is,

$$\begin{gathered} r^2=0.274 \\ =27.4\% \end{gathered}$$

The coefficient of determination, as we know, is a measurement of how much variation in the answers y variable is explained by the least square regression model with the explanatory variable. As a result, the least square regression line employing age as an explanatory variable may explain $27.4$percent of the variation in height.