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For the study of Jordanian children in Exercise 2 , the sample mean hemoglobin level was \(11.3 \mathrm{~g} / \mathrm{dl}\) and the sample standard deviation was \(1.6 \mathrm{~g} / \mathrm{dl} .\) A significance test yields a \(P\) -value of 0.0016 . (a) Explain what it would mean for the null hypothesis to be true in this setting. (b) Interpret the \(P\) -value in context.

Short Answer

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(a) The null hypothesis would be that the hemoglobin level is as expected. (b) A 0.0016 P-value suggests strong evidence against the null hypothesis.

Step by step solution

01

Identify the Null Hypothesis

In hypothesis testing, the null hypothesis (denoted as \( H_0 \)) is a statement of no effect or no difference. In the context of this exercise, the null hypothesis would posit that the average hemoglobin level of Jordanian children is equal to a specific value, usually considered the general population mean or a clinically established threshold.
02

Define Null Hypothesis Meaning in Context

For the null hypothesis in this context, it would mean that there is no significant difference between the sample mean hemoglobin level of Jordanian children and the hypothesized population mean value of hemoglobin levels, suggesting that any observed difference is due to random variation or sampling error.
03

Understand the P-value

The \( P \)-value is the probability of observing data as extreme as, or more extreme than, the observed data, assuming that the null hypothesis is true. It helps determine the strength of the evidence against the null hypothesis.
04

Interpret P-value in Context

A \( P \)-value of 0.0016 indicates that there is only a 0.16% chance of observing a sample mean hemoglobin level as different from the hypothesized population mean as the one observed (11.3 g/dl), if the null hypothesis were true. This suggests strong evidence against the null hypothesis, leading one to consider it likely incorrect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis is a foundational concept. It is represented by the symbol \( H_0 \) and assumes that any observed effect or difference in data arises purely by chance. It essentially states that there is no effect or no difference from what has been assumed to be true.

For the study of Jordanian children and their hemoglobin levels, the null hypothesis could be articulated as the sample mean being equal to a known population mean. This population mean might reflect an average value obtained from broader studies of children, perhaps 12 grams per deciliter in this context. Therefore, the null hypothesis would be: **鈥淭he average hemoglobin level of Jordanian children is 12 g/dl.鈥**

This hypothesis works as a baseline or default assumption in statistical testing. All statistical tests aim to determine if there is enough evidence to reject this default assumption, **thus confirming the presence of a significant effect or difference.** If enough evidence is found, the null hypothesis is rejected; otherwise, it is not.
P-value
The P-value is a critical component of statistical hypothesis testing. It measures the strength of evidence against the null hypothesis. Specifically, the P-value indicates the probability of obtaining results as extreme as the observed results, given that the null hypothesis is correct.

A P-value can help researchers understand how "surprising" or "extreme" their data is under the null hypothesis. In the case of the Jordanian children's study, the P-value is 0.0016. This value means there is a 0.16% chance of obtaining a sample mean hemoglobin level as different from the hypothesized mean (perhaps 12 g/dl) as the one observed, if \( H_0 \) were true.

The lower the P-value, the stronger the evidence against \( H_0 \). A rule of thumb is that a P-value less than 0.05 indicates statistically significant results, prompting researchers to question the validity of \( H_0 \). In this example, a P-value of 0.0016 is considered extremely small, providing compelling evidence to reject the null hypothesis with confidence.
Statistical Significance
Statistical significance is a key outcome in hypothesis testing. It helps researchers determine if the results they observe are meaningful or just due to random variations.

Once the P-value is calculated, it is compared to a pre-determined significance level, often denoted as \( \alpha \). Typical values for \( \alpha \) are 0.05 or 0.01. If the P-value is less than or equal to \( \alpha \), the results are deemed statistically significant. This threshold helps decide whether the null hypothesis should be rejected.

In the study of hemoglobin levels among Jordanian children, the P-value of 0.0016 would typically be compared to a significance level of 0.05. Since 0.0016 is much smaller than 0.05, the results are statistically significant.

This significant outcome suggests the observed difference in hemoglobin levels is likely not due to chance. It provides strong evidence against the null hypothesis. Thus, the findings can confidently support that the true average hemoglobin level in Jordanian children differs from the hypothesized value.

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Most popular questions from this chapter

In Exercises 7 to 10, explain what's wrong with the stated hypotheses. Then give correct hypotheses. A change is made that should improve student satisfaction with the parking situation at a local high school. Right now, \(37 \%\) of students approve of the parking that's provided. The null hypothesis \(H_{0}: p>0.37\) is tested against the alternative \(H_{a}: p=0.37\)

The \(z\) statistic for a test of \(H_{0}: p=0.4\) versus \(H_{a}: p \neq 0.4\) is \(z=2.43 .\) This test is (a) not significant at either \(\alpha=0.05\) or \(\alpha=0.01\). (b) significant at \(\alpha=0.05\) but not at \(\alpha=0.01\). (c) significant at \(\alpha=0.01\) but not at \(\alpha=0.05\). (d) significant at both \(\alpha=0.05\) and \(\alpha=0.01\). (e) inconclusive because we don't know the value of \(\hat{p}\).

A student performs a test of \(H_{0}: p=0.75\) versus \(H_{a}: p>0.75\) and gets a \(P\) -value of \(0.99 .\) The student writes: "Because the \(P\) -value is greater than \(0.75,\) we reject \(H_{0} .\) The data prove that \(H_{a}\) is true." Explain what is wrong with this conclusion.

In the sample, \(\hat{p}=158 / 300=0.527 .\) The resulting \(P\) -value is 0.18 . What is the correct interpretation of this \(P\) -value? (a) Only \(18 \%\) of the city residents support the tax increase. (b) There is an \(18 \%\) chance that the majority of residents supports the tax increase. (c) Assuming that \(50 \%\) of residents support the tax increase, there is an \(18 \%\) probability that the sample proportion would be 0.527 or higher by chance alone. (d) Assuming that more than \(50 \%\) of residents support the tax increase, there is an \(18 \%\) probability that the sample proportion would be 0.527 or higher by chance alone. (e) Assuming that \(50 \%\) of residents support the tax increase, there is an \(18 \%\) chance that the null hypothesis is true by chance alone.

The most important condition for sound conclusions from statistical inference is that (a) the data come from a well-designed random sample or randomized experiment. (b) the population distribution be exactly Normal. (c) the data contain no outliers. (d) the sample size be no more than \(10 \%\) of the population size. (e) the sample size be at least 30 .

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