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91Ó°ÊÓ

In Exercises 7 to 10, explain what's wrong with the stated hypotheses. Then give correct hypotheses. A change is made that should improve student satisfaction with the parking situation at a local high school. Right now, \(37 \%\) of students approve of the parking that's provided. The null hypothesis \(H_{0}: p>0.37\) is tested against the alternative \(H_{a}: p=0.37\)

Short Answer

Expert verified
The correct hypotheses are: \(H_0: p = 0.37\) and \(H_a: p > 0.37\).

Step by step solution

01

Understand the problem

The problem involves hypothesis testing for proportions. The current situation suggests that 37% of students approve of the parking. A change is made to potentially improve this satisfaction level, and we are testing whether there is a statistically significant difference.
02

Identify what's wrong with the hypotheses

The null hypothesis is stated as \(H_0: p > 0.37\) and the alternative \(H_a: p = 0.37\). This setup is incorrect because the null hypothesis should state the status quo or no effect, while the alternative hypothesis should state the potential change. Moreover, the alternative hypothesis should be inequality since we are testing for an improvement.
03

Correct the null hypothesis

The null hypothesis should state that there is no improvement in satisfaction. Since the initial satisfaction level is 37%, the correct null hypothesis should be \(H_0: p = 0.37\).
04

Correct the alternative hypothesis

The alternative hypothesis should reflect the potential improvement in satisfaction, which implies that the proportion of students approving should be greater than the original 37%. Therefore, the correct alternative hypothesis should be \(H_a: p > 0.37\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportions
Proportions are all about understanding parts of a whole. In our exercise scenario, we are dealing with proportions because we're talking about the percentage of students who approve of the parking situation. Out of the whole group, 37% currently approve, which is our initial data point. Whenever you deal with proportions, you're dividing something into smaller parts and then figuring out what fraction or percentage those parts represent. This is essential in hypothesis testing since we often want to see how these proportions change after some improvements or interventions. For instance, if changes were made to increase the satisfaction rate, we would now examine a new proportion of satisfied students to see if it differs from our original 37%. Calculating proportions gives us a quantitative way to measure changes and make informed decisions based on statistical evidence.
Null Hypothesis
The null hypothesis is a cornerstone in hypothesis testing. It is the default assumption that there is no effect or no change from the status quo. In the context of our exercise, the original null hypothesis stated incorrectly. The null should typically reflect that no improvement has happened, aligning with the idea that any changes implemented haven’t altered student satisfaction. Thus, the correct null hypothesis should be \[ H_0: p = 0.37 \] where \(p\) is the true proportion of students who approve. Properly framing the null hypothesis is crucial, as it forms the baseline that statistical tests compare the data against.
Alternative Hypothesis
While the null hypothesis maintains that the existing situation isn't any different, the alternative hypothesis is what drives the quest for change.It suggests that there is a meaningful difference or effect. In our exercise, the alternative hypothesis erroneously stated, called for equality. Instead, it should claim that satisfaction has improved following the changes made. So, the alternative hypothesis should be:\[ H_a: p > 0.37 \]where \(p\) is the proportion of students approving. This hypothesis not only refutes the null but specifies that the expected change is positive. The alternative hypothesis provides direction, focusing the analysis on identifying potential improvements.
Statistical Significance
Statistical significance is the deciding factor in hypothesis testing. It helps determine whether the differences observed are due to random chance or if they are meaningful. When analyzing the difference in student satisfaction proportions, statistical significance tells us if the proportion after changes differs enough from our null hypothesis of 37% approval to conclude that the change was effective. To assess statistical significance, we typically look at the p-value obtained from the data. If this p-value is less than a predetermined threshold (often 0.05), we can state that our results are statistically significant. In such a case, we would reject the null hypothesis, thus supporting the alternative that more students now approve of the parking situation due to the improvements made.

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Most popular questions from this chapter

A drug manufacturer claims that fewer than \(10 \%\) of patients who take its new drug for treating Alzheimer's disease will experience nausea. To test this claim, a significance test is carried out of $$ \begin{array}{l} H_{0}: p=0.10 \\ H_{a}: p<0.10 \end{array} $$ You learn that the power of this test at the \(5 \%\) significance level against the alternative \(p=0.08\) is 0.29 . (a) Explain in simple language what "power \(=0.29 "\) means in this setting. (b) You could get higher power against the same alternative with the same \(\alpha\) by changing the number of measurements you make. Should you make more measurements or fewer to increase power? Explain. (c) If you decide to use \(\alpha=0.01\) in place of \(\alpha=0.05\), with no other changes in the test, will the power increase or decrease? Justify your answer. (d) If you shift your interest to the alternative \(p=0.07\) with no other changes, will the power increase or decrease? Justify your answer.

After checking that conditions are met, you perform a significance test of \(H_{0}: \mu=1\) versus \(H_{a}: \mu \neq 1 .\) You obtain a \(P\) -value of \(0.022 .\) Which of the following must be true? (a) \(A 95 \%\) confidence interval for \(\mu\) will include the value 1 . (b) \(A 95 \%\) confidence interval for \(\mu\) will include the value 0 . (c) \(A 99 \%\) confidence interval for \(\mu\) will include the value 1 . (d) A \(99 \%\) confidence interval for \(\mu\) will include the value 0 . (e) None of these is necessarily true.

A drug manufacturer forms tablets by compressing a granular material that contains the active ingredient and various fillers. The hardness of a sample from each batch of tablets produced is measured to control the compression process. The target value for the hardness is \(\mu=11.5 .\) The hardness data for a random sample of 20 tablets are \(\begin{array}{lllll}11.627 & 11.613 & 11.493 & 11.602 & 11.360 \\ 11.374 & 11.592 & 11.458 & 11.552 & 11.463 \\ 11.383 & 11.715 & 11.485 & 11.509 & 11.429 \\ 11.477 & 11.570 & 11.623 & 11.472 & 11.531\end{array}\) Is there convincing evidence at the \(5 \%\) level that the mean hardness of the tablets differs from the target value?

How well materials conduct heat matters when designing houses, for example. Conductivity is measured in terms of watts of heat power transmitted per square meter of surface per degree Celsius of temperature difference on the two sides of the material. In these units, glass has conductivity about \(1 .\) The National Institute of Standards and Technology provides exact data on properties of materials. Here are measurements of the heat conductivity of 11 randomly selected pieces of a particular type of glass: \({ }^{22}\) \(\begin{array}{llllllllllll}1.11 & 1.07 & 1.11 & 1.07 & 1.12 & 1.08 & 1.08 & 1.18 & 1.18 & 1.18 & 1.12\end{array}\) (a) Is there convincing evidence that the mean conductivity of this type of glass is greater than \(1 ?\) (b) Given your conclusion in part (a), which kind of mistake-a Type I error or a Type II error - could you have made? Explain what this mistake would mean in context.

. You are testing \(H_{0}: \mu=10\) against \(H_{a}: \mu<10\) based on an SRS of 20 observations from a Normal population. The \(t\) statistic is \(t=-2.25\). The \(P\) -value (a) falls between 0.01 and 0.02 . (b) falls between 0.02 and 0.04 . (c) falls between 0.04 and 0.05 . (d) falls between 0.05 and 0.25 . (e) is greater than 0.25 .

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