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To start her old lawn mower, Rita has to pull a cord and hope for some luck. On any particular pull, the mower has a \(20 \%\) chance of starting. (a) Find the probability that it takes her exactly 3 pulls to start the mower. Show your work. (b) Find the probability that it takes her more than 10 pulls to start the mower. Show your work.

Short Answer

Expert verified
(a) 0.128; (b) 0.107

Step by step solution

01

Understanding the Problem

Rita needs to start her lawn mower, which has a 20% probability of starting on any given pull. Her success follows a geometric distribution, where the probability of the event is \( p = 0.2 \). We will calculate the probabilities for specific scenarios using this distribution.
02

Part (a): Probability of Starting on Exactly 3 Pulls - Define Formula

The probability of starting the mower on exactly the 3rd pull can be found using the formula for the geometric distribution:\[P(X = k) = (1-p)^{k-1} \cdot p\]where \( p = 0.2 \) and \( k = 3 \).
03

Part (a): Calculate the Probability

Substitute the values into the formula:\[P(X = 3) = (1 - 0.2)^{3-1} \cdot 0.2 = (0.8)^2 \cdot 0.2\]Calculate:\[P(X = 3) = 0.64 \cdot 0.2 = 0.128\]
04

Part (b): Probability of More Than 10 Pulls - Define Cumulative Probability

For finding the probability that it takes more than 10 pulls to start the mower, we need to calculate \( P(X > 10) \). This can be done using the cumulative distribution function (CDF) of the geometric distribution:\[P(X > n) = (1-p)^n\]where \( p = 0.2 \) and \( n = 10 \).
05

Part (b): Calculate Cumulative Probability

Substitute the values into the CDF:\[P(X > 10) = (1 - 0.2)^{10} = 0.8^{10}\]Calculate:\[P(X > 10) \approx 0.1073741824\]which is approximately 0.107.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a fundamental concept in statistics that measures the likelihood of a certain event happening. When we say that the probability of an event is 0.2 (or 20%), it means there's a 20% chance that the event will occur. In the context of our example, each pull of Rita's mower has a 20% chance of starting the motor. This fixed probability is critical for predicting outcomes in repeated trials.

The basic rule in finding probability involves identifying the possible outcomes of a random process, and then determining how likely each outcome is. For instance, when using the geometric distribution as with Rita's lawn mower, you calculate the probability specifically for each pull attempt:
  • The probability of a successful start on exactly the 3rd attempt is found by multiplying the probabilities of the first two pulls not starting, followed by the third pull being a success.
  • Formally, it's given by the formula for the geometric distribution: \( P(X = k) = (1-p)^{k-1} \cdot p \) where \( p \) is the probability of success on each trial.
This establishes that probabilities for sequential or repeated events require understanding and applying the right formula for accurate outcomes.
Cumulative Distribution Function
The Cumulative Distribution Function, or CDF, captures the idea of accumulating probabilities. It's used to determine the probability that a random variable is less than or equal to a certain value. For the geometric distribution, the CDF can be extremely helpful to find probabilities of outcomes greater than a certain point.

In the exercise, we found \( P(X > 10) \), the probability of more than 10 pulls needed. This is done by first acknowledging that the CDF of a geometric distribution is \( F(n) = 1 - (1-p)^n \), where \( n \) is the number of trials.
  • What we needed to calculate instead was \( 1 - F(n) \), that is, the probability of more than 10 attempts, given by \( P(X > n) = (1-p)^n \).
This technique of using the CDF simplifies calculating probabilities for events greater than a set number. It's crucial for identifying bounds of events, especially in cases involving many trials.
Mathematical Statistics
Mathematical statistics provides the tools necessary for analyzing random processes through distinct distributions, among which the geometric distribution is one. It explores not just raw probabilities, but also ways to interpret and apply these in real-world problems.

Through mathematical statistics, you can:
  • Develop formulas and models for random events, such as using the formula \( P(X = k) = (1-p)^{k-1} \cdot p \) for specific scenarios.
  • Make use of cumulative functions to expand your analysis to more complex queries, like determining \( P(X > n) \) through cumulative probability calculations.
This framework provides comprehensive mechanisms to solve statistical problems and extrapolate findings to similar scenarios, enhancing decision-making and prediction accuracy. In classroom or textbook settings, mastering these statistical tools equips students with the essential analytical skills to approach probabilistic problems strategically.

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