/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Study habits The Survey of Study... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Study habits The Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures academic motivation and study habits. The distribution of SSHA scores among the women at a college has mean 120 and standard deviation 28 , and the distribution of scores among male students has mean 105 and standard deviation \(35 .\) You select a single male student and a single female student at random and give them the SSHA test. (a) Find the mean and standard deviation of the difference (female minus male) between their scores. Interpret each value in context. (b) From the information given, can you find the probability that the woman chosen scores higher than the man? If so, find this probability. If not, explain why you cannot.

Short Answer

Expert verified
(a) Mean is 15, SD is approximately 44.83. (b) Cannot find probability without distribution type.

Step by step solution

01

Define Variables

Let's denote the SSHA score of the female student as \( X \) and the SSHA score of the male student as \( Y \). We are interested in the difference \( D = X - Y \).
02

Calculate Mean of Difference

The mean of the difference \( D = X - Y \) is obtained by subtracting the mean of \( Y \) from the mean of \( X \). This is calculated as: \[ \mu_D = \mu_X - \mu_Y = 120 - 105 = 15 \]. Thus, the mean difference is 15.
03

Calculate Standard Deviation of Difference

The standard deviation of the difference \( D = X - Y \) is calculated using the formula for the standard deviation of the difference of two independent variables: \[ \sigma_D = \sqrt{\sigma_X^2 + \sigma_Y^2} = \sqrt{28^2 + 35^2} \]. Calculating this gives: \[ \sigma_D = \sqrt{784 + 1225} = \sqrt{2009} \approx 44.83 \]. The standard deviation of the difference is approximately 44.83.
04

Analyze Part (b)

To find the probability that the female student's score is higher than the male student's score (i.e., \( D = X - Y > 0 \)), we ideally require knowledge about the distribution of \( D \). With just means and standard deviations, we cannot determine probabilities unless the distribution (such as normal) is specified.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Mean in Context
The mean in statistics is a way to find the average of a set of numbers. It's like trying to find a common level among different values. In the context of study habits, the mean SSHA score for women is 120, and for men, it is 105. The mean helps us understand the central tendency or the expected average score in a specific group.

When we're looking at the difference between these two means, as seen in the step-by-step solution, the calculation is quite simple. We subtract the mean score of males from the mean score of females:
  • Mean of female scores: 120
  • Mean of male scores: 105
  • Difference in means: 120 - 105 = 15

This tells us that, on average, women score 15 points higher than men on the SSHA test. This average difference is crucial as it sets a foundation for comparing their academic motivation and study habits.
Exploring Standard Deviation
Standard deviation is an important concept when we're trying to understand how spread out numbers are around the mean. In simpler terms, it tells us how much scores vary from the average score. A smaller standard deviation means the scores are closely clustered around the mean, while a larger one indicates more spread.

In the given scenario, the standard deviations are:
  • Standard deviation for women: 28
  • Standard deviation for men: 35

The calculation of the standard deviation for the difference in scores involves squaring these values, adding the squares, and taking the square root:
\[ \sigma_D = \sqrt{28^2 + 35^2} = \sqrt{784 + 1225} \approx 44.83 \]
This result, approximately 44.83, means there is a significant variation in the difference between individual scores of men and women.
Understanding Probability in Difference
Probability is a measure of how likely an event is to occur. Here, we want to know the probability that a selected woman's score is higher than a selected man's score, or mathematically, that the difference is greater than zero: \( D = X - Y > 0 \).

To find this probability, we need more than just the mean and standard deviation. We need to know the distribution of these scores. With a normal distribution, calculation is more feasible, but if not specified, assessing probability becomes challenging.

Thus, just knowing the averages and variations won't provide the desired probability unless a normal distribution is assumed or known from additional context. Understanding probability in this context emphasizes the necessity of knowing underlying distributions.
Independent Variables in Statistical Analysis
Independent variables are those whose variations are not affected by other variables in a study. In statistical analysis, understanding independence is crucial as it influences how we calculate means and standard deviations for composite data.

Here, the assumption is that the scores for men and women are independent of each other, meaning one does not influence the other. This assumption is key when combining their variances.
  • If independent: We use the formula for the standard deviation of differences by adding variances (squared standard deviations).
  • If dependent: The method of calculation would change significantly.

Statistical tools often assume independence unless otherwise stated, highlighting its importance for accurate analysis and interpretation of data patterns in study habits.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exercises 27 to 29 refer to the following setting. Choose an American household at random and let the random variable \(X\) be the number of cars (including \(\mathrm{SUVs}\) and light trucks) they own. Here is the probability model if we ignore the few households that own more than 5 cars: \begin{tabular}{lcccccc} \hline Number of cars \(X:\) & 0 & 1 & 2 & 3 & 4 & 5 \\ Probability: & 0.09 & 0.36 & 0.35 & 0.13 & 0.05 & 0.02 \\ \hline \end{tabular} 27\. What's the expected number of cars in a randomly selected American household? (a) 1.00 (b) 1.75 (c) 1.84 (d) 2.00 (e) 2.50

Time and motion A time-and-motion study measures the time required for an assembly-line worker to perform a repetitive task. The data show that the time required to bring a part from a bin to its position on an automobile chassis varies from car to car according to a Normal distribution with mean 11 seconds and standard deviation 2 seconds. The time required to attach the part to the chassis follows a Normal distribution with mean 20 seconds and standard deviation 4 seconds. The study finds that the times required for the two steps are independent. A part that takes a long time to position, for example, does not take more or less time to attach than other parts. (a) What is the distribution of the time required for the entire operation of positioning and attaching a randomly selected part? (b) Management's goal is for the entire process to take less than 30 seconds. Find the probability that this goal will be met for a randomly selected part.

Statistics for investing (3.1) Joe's retirement plan invests in stocks through an "index fund" that follows the behavior of the stock market as a whole, as measured by the Standard \(\&\) Poor's \((\mathrm{S} \& \mathrm{P}) 500\) stock index. Joe wants to buy a mutual fund that does not track the index closely. He reads that monthly returns from Fidelity Technology Fund have correlation \(r=0.77\) with the S\&P 500 index and that Fidelity Real Estate Fund has correlation \(r=0.37\) with the index. (a) Which of these funds has the closer relationship to returns from the stock market as a whole? How do you know? (b) Does the information given tell Joe anything about which fund has had higher returns?

Geometric or not? Determine whether each of the following scenarios describes a geometric setting. If so, define an appropriate geometric random variable. (a) Shuffle a standard deck of playing cards well. Then turn over one card at a time from the top of the deck until you get an ace. (b) Lawrence likes to shoot a bow and arrow in his free time. On any shot, he has about a \(10 \%\) chance of hitting the bull's-eye. As a challenge one day, Lawrence decides to keep shooting until he gets a bull's-eye.

Keno Keno is a favorite game in casinos, and similar games are popular with the states that operate lotteries. Balls numbered 1 to 80 are tumbled in a machine as the bets are placed, then 20 of the balls are chosen at random. Players select numbers by marking a card. The simplest of the many wagers available is "Mark l Number." Your payoff is \(\$ 3\) on a \(\$ 1\) bet if the number you select is one of those chosen. Because 20 of 80 numbers are chosen, your probability of winning is \(20 / 80,\) or \(0.25 .\) Let \(X=\) the net amount you gain on a single play of the game.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.