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Geometric or not? Determine whether each of the following scenarios describes a geometric setting. If so, define an appropriate geometric random variable. (a) Shuffle a standard deck of playing cards well. Then turn over one card at a time from the top of the deck until you get an ace. (b) Lawrence likes to shoot a bow and arrow in his free time. On any shot, he has about a \(10 \%\) chance of hitting the bull's-eye. As a challenge one day, Lawrence decides to keep shooting until he gets a bull's-eye.

Short Answer

Expert verified
Both scenarios describe geometric settings with random variables: (a) cards until an ace (p = 1/13), (b) arrows until bull's-eye (p = 0.10).

Step by step solution

01

Understanding the Geometric Setting

A geometric distribution models the number of trials until the first success in a series of independent Bernoulli trials, each with the same probability of success. The key components are: a series of trials, two possible outcomes per trial (success or failure), and constant probability of success.
02

Analyze Scenario (a) - Deck of Cards

In scenario (a), turning over cards from a shuffled deck until you get an ace fits the definition of a geometric setting. Each card drawn is an independent event with two outcomes (ace or not an ace), and the probability of drawing an ace remains constant at \( \frac{4}{52} = \frac{1}{13} \), since there are 4 aces in a standard 52-card deck.
03

Define Geometric Random Variable for (a)

Let the geometric random variable \( X \) be the number of cards drawn until an ace is obtained. Thus, \( X \) follows a geometric distribution with parameter \( p = \frac{1}{13} \).
04

Analyze Scenario (b) - Shooting Arrows

In scenario (b), Lawrence is shooting arrows until he hits a bull's-eye. Each shot is an independent trial with two possible outcomes (hitting the bull's-eye or not), and the probability of hitting the bull's-eye is consistent at \( p = 0.10 \). This aligns with the conditions of a geometric distribution.
05

Define Geometric Random Variable for (b)

Let the geometric random variable \( Y \) be the number of arrows shot until the first bull's-eye is hit. Thus, \( Y \) follows a geometric distribution with parameter \( p = 0.10 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Random Variable
When trying to understand the concept of a *geometric random variable*, it's important to first get a general idea of how it relates to probability and trials. Imagine you are conducting a series of experiments, where each experiment has the same two outcomes: success or failure. In a geometric setting, you conduct these experiments independently until you achieve your first success. The geometric random variable is a numerical representation that gives you the number of trials needed to get that first success.
In simple terms, if you are turning over cards from a deck until getting an ace, or shooting arrows until hitting a bull's-eye, the geometric random variable would be the number of cards flipped or the number of arrows shot before hitting the target. This focus on counting trials until success is what distinguishes geometric random variables from others. They are perfect for modeling situations where you perform the same task repeatedly and independently until you have success.
Probability of Success
The concept of *probability of success* in a geometric distribution is crucial, as it determines the randomness of your trials. In each trial, you have a constant probability of success, denoted by the symbol \( p \). This **probability does not change** from one trial to the next. For example, if Lawrence, the archer, has a 10% chance of hitting a bull's-eye with each shot, this probability stays at 10% each time he pulls back the bowstring.
Mathematically, this consistency of probability is what defines the trials as *Bernoulli trials*, making the events independent. The probability of success gives a unique parameter to the geometric random variable because it characterizes how quickly or slowly you would expect to achieve your first success.
Bernoulli Trials
*Bernoulli trials* are the backbone of a geometric distribution. Named after Swiss mathematician Jakob Bernoulli, these trials are defined by:
  • A fixed number of trials or experiments
  • Each trial has only two possible outcomes: "success" or "failure"
  • The probability of success \( p \) is the same at each trial
  • The trials are independent, meaning the result of one does not affect the others

In our scenarios, whether drawing cards or shooting arrows, each independent action follows these rules. Each time a card is drawn or an arrow is shot, the outcome does not influence the subsequent attempts. This independence is vital because it ensures the consistency and applicability of the geometric distribution model. Understanding Bernoulli trials helps in mastering any situation where you repeatedly try until you succeed.

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Most popular questions from this chapter

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