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Late flights An airline reports that \(85 \%\) of its flights arrive on time. To find the probability that its next four flights into LaGuardia Airport all arrive on time, can we multiply (0.85)(0.85)(0.85)(0.85)\(?\) Why or why not?

Short Answer

Expert verified
Yes, multiply (0.85)^4 because the flights are independent events.

Step by step solution

01

Understanding the Problem

The problem involves finding the probability of all next four flights arriving on time when each flight has an 85% chance to be on time. This is an example of a binomial probability where each event (flight being on time) is independent.
02

Determine Individual Probability

The probability of one flight arriving on time is given as 85%, which can be expressed as a decimal: 0.85.
03

Independent Events

Since each flight arrival is an independent event, the probability of all four flights arriving on time is the product of the individual probabilities of each flight arriving on time. Thus, we multiply the probability of each event.
04

Calculate the Overall Probability

Multiply the probability of each flight arriving on time to find the overall probability:\[P( ext{all 4 flights on time}) = 0.85 \times 0.85 \times 0.85 \times 0.85\]This simplifies to \((0.85)^4\).
05

Solution Calculation

Calculate \((0.85)^4\) to find the overall probability:\[(0.85)^4 = 0.52200625\]Thus, the probability that all four flights arrive on time is approximately 0.522.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
When dealing with probability, particularly in relation to events occurring in sequence, it's crucial to understand the notion of independent events. Simply put, independent events are scenarios where the outcome of one event doesn't affect the outcome of another. For example, if you're flipping a coin multiple times, the result of your first flip doesn't affect the subsequent flip. Each event stands alone.

In the case of the airline flights, each flight arriving on time is considered an independent event. This means the on-time arrival of one flight does not impact the others. Independence is crucial when you're applying probability calculations, as it allows for the direct multiplication of individual probabilities to find the combined likelihood of several events happening together.

It's impimportant to note that when events are not independent, more complex probability rules and calculations are necessary. However, for this scenario involving flights, assuming independence allows for straightforward multiplication.
Probability Calculation
Calculating probability is all about determining how likely an event is to occur. For a single independent event, probability is expressed as a value between 0 and 1, where 0 means the event cannot happen, and 1 means it is certain. In percentage terms, 0% represents impossibility, while 100% is certainty.

To find the probability of all four flights arriving on time, we use the individual probability expressed as a decimal (0.85 for 85% in this case) and multiply it by itself for each flight. The mathematical operation here is exponentiation since each event's probability is identical and independent:
  • Let's say each flight's likelihood to arrive on time is 0.85. The calculation would look like:
  • \(P(\text{all 4 flights on time}) = 0.85 \times 0.85 \times 0.85 \times 0.85\)
  • which simplifies to \((0.85)^4\).


Performing this exponentiation results in an approximate probability of 0.522. This result tells us there is roughly a 52.2% chance that all four flights will arrive on time. Hence, through simple multiplication, leveraging the fact that the events are independent, we determine the overall probability for multiple events.
AP Statistics
AP Statistics involves the study and application of statistical methods to solve real-world problems. Key topics often include probability, data analysis, and inferential statistics. In the AP Statistics curriculum, problems like the one involving flight arrivals serve to illustrate foundational concepts of probability and independence.

Students learn to approach problems by setting up models — such as those for binomial probabilities. The exercise about the flights entails defining the event (on-time arrival), understanding its probability (85%), recognizing that each event is independent, and then using these insights to calculate the overall probability for a sequence of events. In AP Statistics, these problems help to reinforce understanding by applying theoretical principles to practical situations.

Additionally, through such exercises, students develop critical thinking skills and a methodical approach to problem-solving — skills valuable in higher mathematics and various applications. AP Statistics encourages students to not just compute but also interpret results, thus seeing the big picture rather than disconnected pieces.

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