/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 Testing the test Are false posit... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Testing the test Are false positives too common in some medical tests? Researchers conducted an experiment involving 250 patients with a medical condition and 750 other patients who did not have the medical condition. The medical technicians who were reading the test results were unaware that they were subjects in an experiment. (a) Technicians correctly identified 240 of the 250 patients with the condition. They also identified 50 of the healthy patients as having the condition. What were the false positive and false negative rates for the test? (b) Given that a patient got a positive test result, what is the probability that the patient actually had the medical condition? Show your work.

Short Answer

Expert verified
The false positive rate is 6.7%, the false negative rate is 4%, and the probability of having the condition given a positive result is 82.76%.

Step by step solution

01

Understanding the Problem

In this exercise, we need to analyze test results from a medical study involving 1000 patients, of which 250 had the condition and 750 did not. We are to calculate the false positive and false negative rates and the probability of having the condition given a positive test result.
02

Calculate False Positive Rate

A false positive occurs when the test indicates a condition is present when it's actually not. Technicians identified 50 out of 750 healthy patients as having the condition. The false positive rate is the number of false positives divided by the total number of healthy patients. Calculate: \[\text{False Positive Rate} = \frac{50}{750} = \frac{1}{15} \approx 0.067\]
03

Calculate False Negative Rate

A false negative occurs when the test fails to detect a condition that is present. Technicians failed to identify 10 patients with the condition out of 250 because they correctly identified 240. The false negative rate is the number of false negatives divided by the total number of patients with the condition.Calculate: \[\text{False Negative Rate} = \frac{10}{250} = \frac{1}{25} = 0.04\]
04

Use Bayes' Theorem to Find Probability

We need to calculate the probability that a patient has the condition given a positive test result, which is represented as \(P(\text{Condition} | \text{Positive})\). To find this, apply Bayes' theorem:\[ P(A | B) = \frac{P(B | A) \cdot P(A)}{P(B)} \]For this problem:- \(P(A)\) is the prior probability of having the condition: \(\frac{250}{1000}\).- \(P(B | A)\) is the probability of testing positive given the condition: \(\frac{240}{250}\).- \(P(B)\) is the total probability of testing positive: \(\frac{240 + 50}{1000}\).Calculate:\[P(\text{Condition} | \text{Positive}) = \frac{\frac{240}{250} \times \frac{250}{1000}}{\frac{290}{1000}} = \frac{240}{290} \approx 0.8276\]
05

Conclusion

The false positive rate is approximately 6.7% and the false negative rate is 4%. The probability that a patient actually has the condition given a positive test result is approximately 82.76%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

False Positive Rate
The false positive rate is an important concept in understanding the reliability of medical tests. In simple terms, it refers to the proportion of healthy individuals who incorrectly receive a positive result for a condition they do not have. In the context of the exercise, out of 750 patients without the condition, 50 were inaccurately identified as having it. To calculate the false positive rate, you simply divide the number of false positives (50) by the total number of healthy patients (750). - Formula: - \( \text{False Positive Rate} = \frac{50}{750} = \frac{1}{15} \approx 0.067 \)- This tells us that about 6.7% of the time, the test gives a false alarm. The false positive rate helps us understand how often a test might incorrectly indicate a condition. It's a crucial measure, particularly in screening programs, because high false positive rates can lead to unnecessary stress and further invasive testing for patients. Understanding and managing this rate is vital to enhance the effectiveness and efficiency of medical tests.
False Negative Rate
The false negative rate indicates how frequently a test fails to detect a condition that a patient actually has. This is another critical measure, as missing a diagnosis can be more severe than the inconvenience of a false positive.In our scenario, the test correctly identified 240 out of 250 patients with the condition, meaning it missed 10 patients.To find the false negative rate, divide the number of false negatives (10) by the total number of patients with the condition (250):- Formula: - \( \text{False Negative Rate} = \frac{10}{250} = \frac{1}{25} = 0.04 \)- Therefore, the false negative rate is 4%.This means that out of all the patients who actually have the condition, 4% will receive a negative test result.Understanding this rate is crucial in contexts where missing a disease could lead to significant health consequences. It highlights the importance of a balanced approach in testing to minimize both types of errors.
Conditional Probability
Conditional probability enhances our understanding of how likely an event is, given that another event has occurred.In medical testing, we often want to know the probability that a patient actually has a condition given a positive test result. We can find this using Bayes' Theorem, a key tool in statistics.In this exercise, we seek \( P(\text{Condition} | \text{Positive}) \), or the probability a person has the condition given a positive test result.Bayes' Theorem guides us through considering - the probability of testing positive if one has the condition- the overall probability of having the condition- the total probability of testing positive.Using the exercise data, the calculations are:- \( P(A) \): Probability of having the condition = \( \frac{250}{1000} \)- \( P(B | A) \): Probability of a positive result given the condition = \( \frac{240}{250} \)- \( P(B) \): Total probability of a positive result = \( \frac{290}{1000} \)Applying Bayes' Theorem:- \[ P(\text{Condition} | \text{Positive}) = \frac{\frac{240}{250} \times \frac{250}{1000}}{\frac{290}{1000}} = \frac{240}{290} \approx 0.8276 \] This means there's an 82.76% chance that a positive test result actually indicates the presence of the condition. By understanding conditional probability, healthcare professionals can better interpret test results and make informed decisions regarding patient care.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Lactose intolerance Lactose intolerance causes difficulty in digesting dairy products that contain lactose (milk sugar). It is particularly common among people of African and Asian ancestry. In the United States (ignoring other groups and people who consider themselves to belong to more than one race), \(82 \%\) of the population is white, \(14 \%\) is black, and \(4 \%\) is Asian. Moreover, \(15 \%\) of whites, \(70 \%\) of blacks, and \(90 \%\) of Asians are lactose intolerant. \({ }^{19}\) Suppose we select a U.S. person at random. (a) What is the probability that the person is lactose intolerant? Show your work. (b) Given that the person is lactose intolerant, find the probability that he or she is Asian. Show your work.

Crawl before you walk ( 3.2 ) At what age do babies learn to crawl? Does it take longer to learn in the winter, when babies are often bundled in clothes that restrict their movement? Perhaps there might even be an association between babies' crawling age and the average temperature during the month they first try to crawl (around six months after birth). Data were collected from parents who brought their babies to the University of Denver Infant Study Center to participate in one of a number of studies. Parents reported the birth month and the age at which their child was first able to creep or crawl a distance of 4 feet within one minute. Information was obtained on 414 infants \((208\) boys and 206 girls). Crawling age is given in weeks, and average temperature (in \({ }^{\circ} \mathrm{F}\) ) is given for the month that is six months after the birth month. $$\begin{array}{lcc}\hline & \text { Average } & \text { Average } \\\\\text { Birth month } & \text { crawling age } & \text { temperature } \\\\\text { January } & 29.84 & 66 \\\\\text { February } & 30.52 & 73 \\\\\text { March } & 29.70 & 72 \\\\\text { April } & 31.84 & 63 \\\\\text { May } & 28.58 & 52 \\\\\text { June } & 31.44 & 39 \\\\\text { July } & 33.64 & 33 \\\\\text { August } & 32.82 & 30 \\\\\text { September } & 33.83 & 33 \\\\\text { 0ctober } & 33.35 & 37 \\\\\text { November } & 33.38 & 48 \\\\\text { December } & 32.32 & 57 \\\\\hline\end{array}$$ Analyze the relationship between average crawling age and average temperature. What do you conclude about when babies learn to crawl?

Nickels falling over You may feel it's obvious that the probability of a head in tossing a coin is about \(1 / 2\) because the coin has two faces. Such opinions are not always correct. Stand a nickel on edge on a hard, flat surface. Pound the surface with your hand so that the nickel falls over. Do this 25 times, and record the results. (a) What's your estimate for the probability that the coin falls heads up? Why? (b) Explain how you could get an even better estimate.

You read in a book about bridge that the probability that each of the four players is dealt exactly one ace is about \(0.11 .\) This means that (a) in every 100 bridge deals, each player has one ace exactly 11 times. (b) in 1 million bridge deals, the number of deals on which each player has one ace will be exactly 110,000 . (c) in a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to \(11 \%\) (d) in a very large number of bridge deals, the average number of aces in a hand will be very close to \(0.11 .\) (e) If each player gets an ace in only 2 of the first 50 deals, then each player should get an ace in more than \(11 \%\) of the next 50 deals.

At the gym Suppose that \(10 \%\) of adults belong to health clubs, and \(40 \%\) of these health club members go to the club at least twice a week. What percent of all adults go to a health club at least twice a week? Write the information given in terms of probabilities, and use the general multiplication rule.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.