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Lactose intolerance Lactose intolerance causes difficulty in digesting dairy products that contain lactose (milk sugar). It is particularly common among people of African and Asian ancestry. In the United States (ignoring other groups and people who consider themselves to belong to more than one race), \(82 \%\) of the population is white, \(14 \%\) is black, and \(4 \%\) is Asian. Moreover, \(15 \%\) of whites, \(70 \%\) of blacks, and \(90 \%\) of Asians are lactose intolerant. \({ }^{19}\) Suppose we select a U.S. person at random. (a) What is the probability that the person is lactose intolerant? Show your work. (b) Given that the person is lactose intolerant, find the probability that he or she is Asian. Show your work.

Short Answer

Expert verified
(a) 0.257. (b) Approx. 0.140.

Step by step solution

01

Understand the Problem

We have a total population consisting of whites, blacks, and Asians, each with a different prevalence of lactose intolerance within their group. We need to calculate the overall probability that a randomly selected person is lactose intolerant (part a). Then, we calculate the probability that a lactose intolerant person is Asian (part b).
02

Calculate the Probability of a Person Being Lactose Intolerant (Part a)

To find the overall probability of lactose intolerance, use the law of total probability. The formula is:\[ P(LI) = P(LI|W) \cdot P(W) + P(LI|B) \cdot P(B) + P(LI|A) \cdot P(A) \]Where:- \( P(LI|W) = 0.15 \)- \( P(W) = 0.82 \)- \( P(LI|B) = 0.70 \)- \( P(B) = 0.14 \)- \( P(LI|A) = 0.90 \)- \( P(A) = 0.04 \)Now substitute the values:\[ P(LI) = 0.15 \cdot 0.82 + 0.70 \cdot 0.14 + 0.90 \cdot 0.04 \]Calculate the result to get: \( P(LI) = 0.123 + 0.098 + 0.036 = 0.257 \).
03

Apply Bayes' Theorem to Find Probability of Being Asian Given Lactose Intolerant (Part b)

We need to find \( P(A|LI) \). This can be calculated using Bayes' theorem:\[ P(A|LI) = \frac{P(LI|A) \cdot P(A)}{P(LI)} \]We have:\- \( P(LI|A) = 0.90 \)\- \( P(A) = 0.04 \)\- \( P(LI) = 0.257 \)Substitute these values into the formula:\[ P(A|LI) = \frac{0.90 \cdot 0.04}{0.257} \]Solve the equation to get:\[ P(A|LI) \approx \frac{0.036}{0.257} \approx 0.140 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a fundamental concept in probability theory that allows us to calculate the probability of an event occurring, given that another event has already occurred. For instance, in this exercise, we're dealing with the probability of being lactose intolerant given a specific racial background. This is written as \( P(LI|R) \), where \( LI \) represents lactose intolerance, and \( R \) represents the race (e.g., white, black, or Asian).

In such scenarios, conditional probability enables us to handle and integrate information that is dependent on other specific conditions rather than excluding them from our calculations. It provides a framework for updating probabilities when new relevant data becomes available.

By effectively isolating and considering the information or condition that influences an event, conditional probability allows us to make more specific inferences and calculations, such as understanding the prevalence of lactose intolerance across different races.

Understanding conditional probability is key to interpreting and solving problems where events are not independent, as shown in this exercise.
Bayes' Theorem
Bayes' theorem is a powerful and important tool used to update probabilities based on the occurrence of evidence or new information. It fundamentally interconnects prior knowledge (prior probability) with subsequent information (likelihood), thereby allowing us to revise our beliefs or calculate new probabilities.

In practice, Bayes' theorem helps answer questions like the probability that a person is from a specific group, given that they are lactose intolerant. This is expressed as \( P(A|LI) \) in the exercise. Bayes' theorem combines the information about how common lactose intolerance is among Asians (\( P(LI|A) \)) and how common Asians are in the population (\( P(A) \)) to find the needed probability.
  • Bayes' theorem formula: \[ P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)} \] This involves:
    • \( P(A|B) \): Probability of A occurring given B has occurred (posterior probability).
    • \( P(B|A) \): Probability of B occurring given A has occurred (likelihood).
    • \( P(A) \): Initial (prior) probability of A.
    • \( P(B) \): Probability of B (marginal likelihood).

Bayes' theorem, hence, allows for a structured approach in solving problems where probability conditions depend on observed evidence, making it an essential concept in statistical inference.
Law of Total Probability
The law of total probability is an essential principle when dealing with composite events and is particularly useful in scenarios where all potential outcomes need their probabilities assessed. In this exercise, the law helps in finding the probability of being lactose intolerant regardless of racial background.

Simply put, it's about adding up all the probabilities of an event, considering every possible scenario. Thus, if an event can occur due to several exclusive paths, the law of total probability gives the overall probability by looking at the contribution from each path.
  • Formula in this context: \[ P(LI) = P(LI|W) \cdot P(W) + P(LI|B) \cdot P(B) + P(LI|A) \cdot P(A) \] where:
    • \( P(LI|W) \), \( P(LI|B) \), and \( P(LI|A) \) are the conditional probabilities of being lactose intolerant given white, black, and Asian ancestry respectively.
    • \( P(W) \), \( P(B) \), \( P(A) \) are the probabilities of randomly selecting a person from each racial group.

Using this rule, you can efficiently determine the overall probability for events with multiple associated conditions or subgroups, as is done here with the different racial demographics and their respective lactose intolerance rates. This technique simplifies calculating probabilities across diverse scenarios, improving comprehension and accuracy.

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Most popular questions from this chapter

Education among young adults Choose a young adult (aged 25 to 29 ) at random. The probability is 0.13 that the person chosen did not complete high school, 0.29 that the person has a high school diploma but no further education, and 0.30 that the person has at least a bachelor's degree. (a) What must be the probability that a randomly chosen young adult has some education beyond high school but does not have a bachelor's degree? Why? (b) What is the probability that a randomly chosen young adult has at least a high school education? Which rule of probability did you use to find the answer?

Monty Hall problem In Parade magazine, a reader posed the following question to Marilyn vos Savant and the "Ask Marilyn" column: Suppose you're on a game show, and you're given the choice of three doors. Behind one door is a car, behind the others, goats. You pick a door, say \(\\# 1,\) and the host, who knows what's behind the doors, opens another door, say # \(3,\) which has a goat. He says to you, "Do you want to pick door # \(2 ?\) Is it to your advantage to switch your choice of doors? \(^{4}\) The game show in question was Let's Make a Deal and the host was Monty Hall. Here's the first part of Marilyn's response: "Yes; you should switch. The first door has a \(1 / 3\) chance of winning, but the second door has a \(2 / 3\) chance." Thousands of readers wrote to Marilyn to disagree with her answer. But she held her ground. (a) Use an online Let's Make a Deal applet to perform at least 50 repetitions of the simulation. Record whether you stay or switch (try to do each about half the time) and the outcome of each repetition. (b) Do you agree with Marilyn or her readers? Explain.

Crawl before you walk ( 3.2 ) At what age do babies learn to crawl? Does it take longer to learn in the winter, when babies are often bundled in clothes that restrict their movement? Perhaps there might even be an association between babies' crawling age and the average temperature during the month they first try to crawl (around six months after birth). Data were collected from parents who brought their babies to the University of Denver Infant Study Center to participate in one of a number of studies. Parents reported the birth month and the age at which their child was first able to creep or crawl a distance of 4 feet within one minute. Information was obtained on 414 infants \((208\) boys and 206 girls). Crawling age is given in weeks, and average temperature (in \({ }^{\circ} \mathrm{F}\) ) is given for the month that is six months after the birth month. $$\begin{array}{lcc}\hline & \text { Average } & \text { Average } \\\\\text { Birth month } & \text { crawling age } & \text { temperature } \\\\\text { January } & 29.84 & 66 \\\\\text { February } & 30.52 & 73 \\\\\text { March } & 29.70 & 72 \\\\\text { April } & 31.84 & 63 \\\\\text { May } & 28.58 & 52 \\\\\text { June } & 31.44 & 39 \\\\\text { July } & 33.64 & 33 \\\\\text { August } & 32.82 & 30 \\\\\text { September } & 33.83 & 33 \\\\\text { 0ctober } & 33.35 & 37 \\\\\text { November } & 33.38 & 48 \\\\\text { December } & 32.32 & 57 \\\\\hline\end{array}$$ Analyze the relationship between average crawling age and average temperature. What do you conclude about when babies learn to crawl?

The birthday problem What's the probability that in a randomly selected group of 30 unrelated people, at least two have the same birthday? Let's make two assumptions to simplify the problem. First, we'll ignore the possibility of a February 29 birthday. Second, we assume that a randomly chosen person is equally likely to be born on each of the remaining 365 days of the year. (a) How would you use random digits to imitate one repetition of the process? What variable would you measure? (b) Use technology to perform 5 repetitions. Record the outcome of each repetition. (c) Would you be surprised to learn that the theoretical probability is 0.71 ? Why or why not?

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