/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Taking the train According to Ne... [FREE SOLUTION] | 91影视

91影视

Taking the train According to New Jersey Transit, the 8: 00 A.M. weekday train from Princeton to New York City has a \(90 \%\) chance of arriving on time. To test this claim, an auditor chooses 6 weekdays at random during a month to ride this train. The train arrives late on 2 of those days. Does the auditor have convincing evidence that the company's claim isn't true? Design and carry out a simulation to estimate the probability that a train with a \(90 \%\) chance of arriving on time each day would be late on 2 or more of 6 days. Follow the four-step process.

Short Answer

Expert verified
The auditor lacks convincing evidence to dispute the claim if the probability is not significantly low.

Step by step solution

01

State the Hypotheses

The null hypothesis ( H鈧) is that the train arrives on time 90% of the days, as claimed by the company. The alternative hypothesis ( H鈧) is that the train does not have a 90% chance of arriving on time.
02

Define the Simulation Methodology

To simulate the probability that the train arrives late, consider each day as a Bernoulli trial with a success probability of 0.10 (being late). Use a random number generator for 6 trials and count the number of days the train could be late.
03

Conduct Repeated Simulations

Repeat the simulation for a large number of trials, such as 1,000 times. For each trial, log whether there were 2 or more late arrivals out of 6 weekdays.
04

Analyze Simulation Results

Calculate the proportion of the simulations where 2 or more trains are late. This proportion approximates the probability of observing 2 or more late arrivals under the company's claim.
05

Make a Conclusion

If the simulated probability is low (typically less than 5%), conclude there is convincing evidence against the company's claim. Otherwise, conclude there is not enough evidence to dispute the claim.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simulation
Simulation is a powerful technique often used in hypothesis testing scenarios. It's like a virtual experiment where we mimic real-world operations using computer-based methods. In our exercise, we're simulating the train's arrival times to understand if the company's claim holds true.

The main steps in simulation involve generating possible outcomes based on the assumed probabilities. We start by defining each day as an independent trial where the train can either be on time or late. This simplifies the problem because we only need to determine how frequently the unlikely event鈥攖wo or more late arrivals鈥攈appens in those 6 days. These trials are repeated multiple times, often thousands, to ensure that our simulated data accurately reflects what might happen in reality.

By evaluating the data generated in these simulations, we compare its results to our null hypothesis. If what we observe in the simulations is highly unlikely under the null hypothesis, we may have enough evidence to reject it.
Probability
Probability is a measure of how likely an event is to occur. In this problem, each train ride has a probability of arriving on time, and conversely, a probability of arriving late.

The company's reported probability is that the train will be on time 90% of the time. Therefore, the probability of the train being late any given day is 10%, since probabilities for all possible outcomes (on time or late) have to add up to 100%. We can express these probabilities using mathematical notation: if the event of arriving on time is represented by "success," then \[ P( ext{success}) = 0.90 \] and \[ P( ext{late}) = 0.10 \].

In simulations, we use these probabilities to generate outcomes over many repetitions, which allows us to estimate the likelihood of observing specific patterns like the train being late on 2 or more days out of 6. Each outcome in the simulation contributes to building a probability distribution of possible outcomes.
Bernoulli Trial
A Bernoulli trial is a random experiment where there are only two possible outcomes鈥"success" or "failure." It is named after the Swiss mathematician Jacob Bernoulli.

In the context of the exercise, each day the train can either be late ('success' for our purposes since we are interested in late days) or on time (failure in this case). With a 10% chance of being late, each day essentially represents a Bernoulli trial. The concept is simple yet incredibly powerful because it allows us to apply probability theory to many real-world binary situations by considering each outcome to be an independent trial. By conducting these trials repeatedly (in our case, 6 times for each simulation), we can gather data about the train's punctuality.

This simplification makes it easier to apply statistical methods to predict and analyze the likelihood of certain outcomes, such as the train being late more often than stated by New Jersey Transit.
Null Hypothesis
The null hypothesis ( H鈧) is an essential concept in hypothesis testing. It is a statement that indicates no change or no effect, and in our problem, it suggests that the claim by New Jersey Transit is true. Specifically, the null hypothesis here is that the train arrives on time 90% of the time. It's the benchmark against which we will compare our observed data鈥攖he 2 days out of 6 that the train was late.

To determine whether there is enough evidence to reject the null hypothesis, we carry out a thorough analysis of the simulation results. We assess if the probability of observing such a pattern of late arrivals is so low under the null hypothesis that we should consider accepting the alternative hypothesis鈥 H鈧, which indicates that the train doesn't meet the 90% on-time rate. In essence, the null hypothesis serves as the status quo, and the entire objective of our hypothesis testing process is to evaluate the evidence and decide if it's convincing enough to overturn this status quo.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fill 'er up! In a recent month, \(88 \%\) of automobile drivers filled their vehicles with regular gasoline, \(2 \%\) purchased midgrade gas, and \(10 \%\) bought pre- mium gas. \({ }^{18}\) Of those who bought regular gas, \(28 \%\) paid with a credit card; of customers who bought midgrade and premium gas, \(34 \%\) and \(42 \%\), respectively, paid with a credit card. Suppose we select a customer at random. (a) Draw a tree diagram to represent this situation. (b) Find the probability that the customer paid with a credit card. Show your work. (c) Given that the customer paid with a credit card, find the probability that she bought premium gas. Show your work.

Common names The Census Bureau says that the 10 most common names in the United States are (in order) Smith, Johnson, Williams, Brown, Jones, Miller, Davis, Garcia, Rodriguez, and Wilson. These names account for \(9.6 \%\) of all U.S. residents. Out of curiosity, you look at the authors of the textbooks for your current courses. There are 9 authors in all. Would you be surprised if none of the names of these authors were among the 10 most common? (Assume that authors' names are independent and follow the same probability distribution as the names of all residents.)

Free throws A basketball player has probability 0.75 of making a free throw. Explain how you would use each chance device to simulate one free throw by the player. (a) A standard deck of playing cards (b) Table D of random digits (c) A calculator or computer's random integer generator

Facebook versus YouTube A recent survey suggests that \(85 \%\) of college students have posted a profile on Facebook, \(73 \%\) use YouTube regularly, and \(66 \%\) do both. Suppose we select a college student at random and learn that the student has a profile on Facebook. Find the probability that the student uses YouTube regularly. Show your work.

Late flights An airline reports that \(85 \%\) of its flights arrive on time. To find the probability that its next four flights into LaGuardia Airport all arrive on time, can we multiply (0.85)(0.85)(0.85)(0.85)\(?\) Why or why not?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.