/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Refer to the following setting. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Refer to the following setting. The National Longitudinal Study of Adolescent Health interviewed a random sample of 4877 teens (grades 7 to 12 ). One question asked was "What do you think are the chances you will be married in the next ten years?" Here is a two-way table of the responses by gender: \({ }^{28}\) $$ \begin{array}{lcc} \hline & \text { Female } & \text { Male } \\ \text { Almost no chance } & 119 & 103 \\ \text { Some chance, but probably not } & 150 & 171 \\ \text { A 50-50 chance } & 447 & 512 \\ \text { A good chance } & 735 & 710 \\ \text { Almost certain } & 1174 & 756 \\ \hline \end{array} $$ The appropriate null hypothesis for performing a chi-square test is that (a) equal proportions of female and male teenagers are almost certain they will be married in 10 years. (b) there is no difference between the distributions of female and male teenagers' opinions about marriage in this sample. (c) there is no difference between the distributions of female and male teenagers' opinions about marriage in the population. (d) there is no association between gender and opinion about marriage in the sample. (e) there is no association between gender and opinion about marriage in the population.

Short Answer

Expert verified
The correct answer is (e).

Step by step solution

01

Understand the Chi-Square Test Objective

The chi-square test of independence is used to determine if there is an association between two categorical variables. In this case, the variables are gender and opinion about future marriage.
02

Identify the Null and Alternative Hypotheses

The null hypothesis ( H_0 ) generally states that there is no association between the variables being studied. Based on the context of the chi-square test, we can identify the null hypothesis related to gender and marriage opinion in the population.
03

Interpret the Choices

Each choice provides a different interpretation of what the null hypothesis could be. We need to select the one that reflects no association between the variables in the context of the population as the chi-square test typically concerns population-level inferences.
04

Determine the Correct Answer

The correct null hypothesis that matches the scenario of a chi-square test for independence is option (e): "there is no association between gender and opinion about marriage in the population." This states that gender and opinion on marriage are independent in the population, which aligns with the objective of the chi-square test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Categorical Variables
Categorical variables are variables that classify data into distinct categories or groups. These are typically qualitative in nature, rather than numerical. For example, in a survey about opinions on marriage, gender is a categorical variable, with categories like 'male' and 'female'. Another categorical variable in this context is the opinion on the likelihood of getting married, with categories like 'almost no chance', 'some chance', 'a 50-50 chance', 'a good chance', and 'almost certain'.

Understanding categorical variables is key because they allow us to segment data in ways that can reveal patterns and relationships between these segments. For instance, by examining responses separately for males and females, researchers can investigate if there's a gender-based difference in marriage expectations.
Null Hypothesis
In statistics, a null hypothesis is a kind of default position that indicates no association between the variables under study. It assumes that any kind of difference or significance seen in the data is due to chance. In the context of chi-square tests for independence, a typical null hypothesis would state that there is no association between the categorical variables being examined.

For instance, when considering the question of whether gender influences opinions about marriage, the null hypothesis would be that gender and opinion are independent, meaning one's gender does not affect or change one's opinion on marriage likelihood. This provides a starting point for statistical analysis, as the chi-square test will determine whether there is enough evidence to reject this assumption.
Statistical Independence
Statistical independence refers to a scenario where the occurrence of one event does not affect the probability of another event happening. In the context of a chi-square test for independence, two categorical variables are said to be statistically independent if the distribution of one variable is the same across the levels of the other variable.

In our example, we're testing whether gender and opinion about future marriage are independent. If they are, knowing someone's gender wouldn’t provide any additional information about their opinion on the likelihood of marriage. The chi-square test helps us assess this by comparing observed frequencies in a contingency table to expected frequencies, assuming independence. If observed and expected frequencies differ significantly, it suggests a possible association.
Population Inference
Population inference refers to the process of using data from a sample to make generalizations about a larger population. In statistical tests like the chi-square test, we often analyze data from a sample and then try to infer if the patterns observed apply to the larger group as a whole.

For example, by using responses from 4877 teens regarding marriage expectations, researchers can infer whether these patterns likely hold true for all teens in the same age range. The null hypothesis often frames these inferences; in this context, it would suggest that any observed association between gender and marriage likelihood in the sample is likely to apply to the larger population as well. The chi-square test helps validate whether we can confidently make such an inference or whether the pattern seen might be the result of sampling variability.

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Most popular questions from this chapter

Exercises 59 to 60 refer to the following setting. For their final project, a group of AP \(^{\otimes}\) Statistics students investigated the following question: "Will changing the rating scale on a survey affect how people answer the question?" To find out, the group took an SRS of 50 students from an alphabetical roster of the school's just over 1000 students. The first 22 students chosen were asked to rate the cafeteria food on a scale of 1 (terrible) to 5 (excellent). The remaining 28 students were asked to rate the cafeteria food on a scale of 0 (terrible) to 4 (excellent). Here are the data: $$ \begin{array}{lcccrc} &{1 \text { to 5 scale }} \\ \text { Rating } & 1 & 2 & 3 & 4 & 5 \\ \text { Frequency } & 2 & 3 & 1 & 13 & 3 \\ \hline & {0 \text { to 4 scale }} \\ \text { Rating } & 0 & 1 & 2 & 3 & 4 \\ \text { Frequency } & 0 & 0 & 2 & 18 & 8 \\ \hline \end{array} $$ $$ \text { Design and analysis }(4.2) $$ (a) Was this an observational study or an experiment? Justify your answer. (b) Explain why it would not be appropriate to perform a chi-square test in this setting.

Skittles Statistics teacher Jason Molesky contacted Mars, Inc., to ask about the color distribution for Skittles candies. Here is an excerpt from the response he received: "The original flavor blend for the SKITTLES BITE SIZE CANDIES is lemon, lime, orange, strawberry and grape. They were chosen as a result of consumer preference tests we conducted. The flavor blend is 20 percent of each flavor." (a) State appropriate hypotheses for a significance test of the company's claim. (b) Find the expected counts for a bag of Skittles with 60 candies. (c) How large a \(\chi^{2}\) statistic would you need to have significant evidence against the company's claim at the \(\alpha=0.05\) level? At the \(\alpha=0.01\) level? (d) Create a set of observed counts for a bag with 60 candies that gives a \(P\) -value between 0.01 and \(0.05 .\) Show the calculation of your chi-square statistic.

Benford's law Faked numbers in tax returns, invoices, or expense account claims often display patterns that aren't present in legitimate records. Some patterns are obvious and easily avoided by a clever crook. Others are more subtle. It is a striking fact that the first digits of numbers in legitimate records often follow a model known as Benford's law. \({ }^{3}\) Call the first digit of a randomly chosen record \(X\) for short. Benford's law gives this probability model for \(X\) (note that a first digit can't be 0 ): $$ \begin{array}{lccccccccc} \hline \text { First digit: } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\ \text { Probability: } & 0.301 & 0.176 & 0.125 & 0.097 & 0.079 & 0.067 & 0.058 & 0.051 & 0.046 \\ \hline \end{array} $$ A forensic accountant who is familiar with Benford's law inspects a random sample of 250 invoices from a company that is accused of committing fraud. The table below displays the sample data. $$ \begin{array}{lcrrrrrrrr} \hline \text { First digit: } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\ \text { Count: } & 61 & 50 & 43 & 34 & 25 & 16 & 7 & 8 & 6 \\ \hline \end{array} $$ (a) Are these data inconsistent with Benford's law? Carry out an appropriate test at the \(\alpha=0.05\) level to support your answer. If you find a significant result, perform a follow-up analysis. (b) Describe a Type I error and a Type II error in this setting, and give a possible consequence of each. Which do you think is more serious?

When analyzing survey results from a two-way table, the main distinction between a test for independence and a test for homogeneity is (a) how the degrees of freedom are calculated. (b) how the expected counts are calculated. (c) the number of samples obtained. (d) the number of rows in the two-way table. (e) the number of columns in the two-way table.

Roulette Casinos are required to verify that their games operate as advertised. American roulette wheels have 38 slots -18 red, 18 black, and 2 green. In one casino, managers record data from a random sample of 200 spins of one of their American roulette wheels. The one-way table below displays the results. $$ \begin{array}{lccc} \hline \text { Color: } & \text { Red } & \text { Black } & \text { Green } \\\ \text { Count: } & 85 & 99 & 16 \\ \hline \end{array} $$ (a) State appropriate hypotheses for testing whether these data give convincing evidence that the distribution of outcomes on this wheel is not what it should be. (b) Calculate the expected counts for each color. Show your work.

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