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Broken crackers We don't like to find broken crackers when we open the package. How can makers reduce breaking? One idea is to microwave the crackers for 30 seconds right after baking them. Breaks start as hairline cracks called "checking." Randomly assign 65 newly baked crackers to the microwave and another 65 to a control group that is not microwaved. After one day, none of the microwave group and 16 of the control group show checking.

Short Answer

Expert verified
Microwaving likely reduces checking as none of the microwaved crackers showed signs.

Step by step solution

01

Define the Hypothesis

Start by defining the null and alternative hypotheses. The null hypothesis (H鈧) is that microwaving has no effect on the number of crackers showing checking. The alternative hypothesis (H鈧) is that microwaving reduces the number of crackers showing checking.
02

Identify the Data

You have 65 microwaved crackers and 65 control crackers. After one day, 0 of the microwaved crackers and 16 of the control group show checking.
03

Calculate the Proportion

Calculate the proportion of checked crackers in both groups. For the control group, this is \( \frac{16}{65} \) or approximately 0.246. For the microwaved group, it is \( \frac{0}{65} = 0 \).
04

Choose a Statistical Test

Use a proportion test to compare the two groups. The test will help determine if the difference in proportions is statistically significant.
05

Perform the Proportion Test

Conduct the test comparing \( p_1 = 0.246 \) (control) and \( p_2 = 0 \) (microwave). Evaluate the p-value from the test statistics.
06

Make a Decision

If the p-value is less than the significance level (usually 0.05), reject the null hypothesis. Otherwise, do not reject it.
07

Conclusion

Based on the test results, conclude whether microwaving significantly reduces checking. Given the results (0 vs 16), it is likely that microwaving helps reduce the checking.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Test
A proportion test is a statistical method used to determine if there are significant differences between the proportions of two groups. In the case of the broken crackers exercise, the test compares two proportions: one from the microwaved group and one from the control group. Here's how it works:

Proportion tests are helpful when dealing with categorical data, especially when you're interested in observing frequency differences, like the occurrence of 'checking' among crackers.

This analysis allows for comparing the proportion of checked crackers in both groups, which were calculated as approximately 0.246 for the control group and 0 for the microwaved group. By looking at these proportions, we can see a potential effect of microwaving on reducing cracker checking.

If you want to conduct this test, follow these steps:
  • Calculate the proportion for each group.
  • Set up the proportion test using these values.
  • Determine if the difference between these proportions is statistically significant by evaluating the test's p-value.
Null Hypothesis
The null hypothesis is a foundational concept in hypothesis testing. It is the default assumption that there is no effect or difference in a study. In our cracker experiment, the null hypothesis states that microwaving the crackers does not change the proportion of checking compared to crackers that were not microwaved.

This hypothesis acts as a starting point for statistical testing, and it's what researchers aim to test or challenge. During the testing process, you'll compare your results to this null hypothesis to determine whether the data provides enough evidence to reject it.

Remember, in any test scenario:
  • The null hypothesis is usually determined before collecting any data.
  • It's often represented as H鈧.
  • Testing against this helps to determine if observed differences are due to random chance.
Without statistical evidence, we retain the null hypothesis, asserting that any observed effect is not significant.
Alternative Hypothesis
The alternative hypothesis is central to hypothesis testing, representing a contrast to the null hypothesis. It suggests that there is an effect or a difference due to the factor being tested.

In this cracker scenario, the alternative hypothesis was that microwaving reduces the incidence of checking compared to not microwaving. This hypothesis is symbolized as H鈧.

Key aspects of alternative hypotheses include:
  • They reflect the researcher's prediction.
  • When the p-value from a statistical test is less than the significance level (often set at 0.05), the alternative hypothesis is accepted.
  • It drives the research design and data collection, focusing on finding evidence to support it.
In this case, the striking absence of checking in the microwaved group compared to the control group suggests support for the alternative hypothesis, indicating a beneficial effect of microwaving.
Statistical Significance
Statistical significance is crucial in determining whether an observed effect or difference is likely not due to random chance. When we find statistical significance, it means the effect is likely genuine and meaningful.

In research, statistical significance is often gauged by a metric known as the p-value. The accepted threshold for significance is typically a p-value of less than 0.05. If the p-value calculated from the test is below this threshold, we can reject the null hypothesis.

In the context of the cracker experiment, calculating statistical significance involves evaluating whether the zero checking in the microwaved crackers is not by mere chance but by the treatment effect.

Steps to check for statistical significance include:
  • Conduct the proportion test based on the collected data.
  • Calculate the p-value.
  • Compare the p-value to your significance level (usually 0.05).
If the p-value is low, this suggests that microwaving the crackers is effective in reducing checking, allowing us to confidently support the alternative hypothesis.

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Most popular questions from this chapter

Listening to rap Is rap music more popular among young blacks than among young whites? A sample survey compared 634 randomly chosen blacks aged 15 to 25 with 567 randomly selected whites in the same age group. It found that 368 of the blacks and 130 of the whites listened to rap music every day. (a) Calculate the standard error of the sampling distribution of the difference in the sample proportions (blacks - whites). What information does this value provide? (b) Construct and interpret a \(95 \%\) confidence interval for the difference between the proportions of black and white young people who listen to rap every day.

State which inference procedure from Chapter \(8,9,\) or 10 you would use. Be specific. For example, you might say, "Two-sample z test for the difference between two proportions." You do not need to carry out any procedures. Which inference method? (a) Drowning in bathtubs is a major cause of death in children less than 5 years old. A random sample of parents was asked many questions related to bathtub safety. Overall, \(85 \%\) of the sample said they used baby bathtubs for infants. Estimate the percent of all parents of young children who use baby bathtubs. (b) How seriously do people view speeding in comparison with other annoying behaviors? A large random sample of adults was asked to rate a number of behaviors on a scale of 1 (no problem at all) to 5 (very severe problem ). Do speeding drivers get a higher average rating than noisy neighbors? (c) You have data from interviews with a random sample of students who failed to graduate from a particular college in 7 years and also from a random sample of students who entered at the same time and did graduate. You will use these data to compare the percents of students from rural backgrounds among dropouts and graduates. (d) Do experienced computer game players earn higher scores when they play with someone present to cheer them on or when they play alone? Fifty teenagers with experience playing a particular computer game have volunteered for a study. We randomly assign 25 of them to play the game alone and the other 25 to play the game with a supporter present. Each player's score is recorded.

Who tweets? Do younger people use Twitter more often than older people? In a random sample of 316 adult Internet users aged 18 to \(29,26 \%\) used Twitter. In a separate random sample of 532 adult Internet users aged 30 to \(49,14 \%\) used Twitter. \({ }\) (a) Calculate the standard error of the sampling distribution of the difference in the sample proportions (younger adults - older adults). What information does this value provide? (b) Construct and interpret a \(90 \%\) confidence interval for the difference between the true proportions of adult Internet users in these age groups who use Twitter.

The researchers report that the results were statistically significant at the \(1 \%\) level. Which of the following is the most appropriate conclusion? (a) Because the \(P\) -value is less than \(1 \%\), fail to reject \(H_{0}\). There is not convincing evidence that the proportion of male college students in the study who worked for pay last summer is different from the proportion of female college students in the study who worked for pay last summer. (b) Because the \(P\) -value is less than \(1 \%\), fail to reject \(H_{0}\). There is not convincing evidence that the proportion of all male college students who worked for pay last summer is different from the proportion of all female college students who worked for pay last summer.

Which of the following is the correct margin of error for a \(99 \%\) confidence interval for the difference in the proportion of male and female college students who worked for pay last summer? (a) \(2.576 \sqrt{\frac{0.851(0.149)}{550}+\frac{0.851(0.149)}{500}}\) (b) \(2.576 \sqrt{\frac{0.851(0.149)}{1050}}\) (c) \(2.576 \sqrt{\frac{0.880(0.120)}{550}+\frac{0.820(0.180)}{500}}\) (d) \(1.960 \sqrt{\frac{0.851(0.149)}{550}+\frac{0.851(0.149)}{500}}\) (e) \(1.960 \sqrt{\frac{0.880(0.120)}{550}+\frac{0.820(0.180)}{500}}\)

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