/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Does breast-feeding weaken bones... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Does breast-feeding weaken bones? Breast-feeding mothers secrete calcium into their milk. Some of the calcium may come from their bones, so mothers may lose bone mineral. Researchers compared a random sample of 47 breast-feeding women with a random sample of 22 women of similar age who were neither pregnant nor lactating. They measured the percent change in the bone mineral content (BMC) of the women's spines over three months. Comparative boxplots and summary statistics for the data from Fathom are shown below. \({ }^{36}\) (a) Based on the graph and numerical summaries, write a few sentences comparing the percent changes in BMC for the two groups. (b) Is the mean change in BMC significantly lower for the mothers who are breast-feeding? Give appropriate evidence to justify your answer. (c) Can we conclude that breast-feeding causes a mother's bones to weaken? Why or why not?

Short Answer

Expert verified
Breast-feeding mothers show a lower mean BMC change, but we cannot conclude causation due to the study's design.

Step by step solution

01

Analyze the Boxplots

Examine the comparative boxplots provided. Look for differences in the centers, spreads, and any potential outliers between the two groups - breast-feeding women and the control group. Note if the median for the breast-feeding group is lower than the control group and observe the interquartile ranges and any apparent outliers.
02

Examine Summary Statistics

Review the numerical summary statistics provided such as the mean, median, and standard deviation for both groups. Note the mean change in BMC for breast-feeding women and compare it to the mean for the control group. Also, consider the standard deviations to assess the variability within each group.
03

Conduct Hypothesis Testing for Part (b)

To determine if the mean change in BMC is significantly lower for breast-feeding mothers, perform a two-sample t-test. - **Null Hypothesis (H0):** There is no difference in the mean change of BMC between breast-feeding mothers and the control group. - **Alternative Hypothesis (H1):** The mean change in BMC is lower for breast-feeding mothers than for the control group. Calculate the t-statistic and corresponding p-value using the means, standard deviations, and sample sizes of both groups. A low p-value (typically less than 0.05) would indicate significant evidence against the null hypothesis.
04

Interpret the Results of the Hypothesis Test

Based on the p-value from the t-test, determine whether the evidence is significant enough to conclude that the mean change in BMC is lower for breast-feeding mothers. If the p-value is below the significance level (e.g., 0.05), reject the null hypothesis.
05

Discuss Causation for Part (c)

Regardless of the statistical significance found in Step 4, discuss whether the study design allows for causal inference. Since this is an observational study, we cannot conclude causation; we can only observe an association between breast-feeding and changes in bone mineral content. Other confounding factors may contribute to the observed result.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Comparative Boxplots
Comparative boxplots are a powerful visual tool in statistics used to compare distributions across different groups. They provide a clear depiction of the center, spread, and potential outliers of the data, making it easier to identify patterns or differences between the groups. In this study, we have two groups: breast-feeding women and women who are neither pregnant nor lactating.

Key features to look for in comparative boxplots include:
  • Median: This line inside the box represents the midpoint of the data. If the median of one group is lower than the other, it may suggest a difference in central tendency.
  • Interquartile Range (IQR): The length of the box shows the spread of the middle 50% of the data. A larger IQR implies greater variability within the group.
  • Outliers: Points outside the "whiskers" are considered outliers. These can affect the statistical results and interpretations.
By analyzing the boxplots for this study, you can quickly assess whether breast-feeding mothers tend to have a lower bone mineral content (BMC) compared to the control group women, by looking for these differences visually.
Two-sample t-test
A two-sample t-test is commonly used to compare the means of two independent groups, helping determine if there is a statistically significant difference between them. In this study, the researchers are interested in seeing if the breast-feeding mothers have a significantly lower mean change in bone mineral content compared to the other group.

To perform a two-sample t-test, follow these steps:
  • Formulate hypotheses: The null hypothesis ( H_0 ) assumes no difference in means, while the alternative hypothesis ( H_1 ) suggests that the breast-feeding mothers' mean change is lower.
  • Calculate test statistic: Use the means, standard deviations, and sample sizes to find the t-value, which tells how far, in standard deviation units, the observed mean is from the null hypothesis.
  • Find p-value: The p-value indicates the probability of observing the data if the null hypothesis is true. A value less than 0.05 typically suggests significant evidence against the null hypothesis.
By determining the p-value, you can conclude whether there is enough evidence to claim that breast-feeding lowers BMC compared to the control group.
Observational Study
In an observational study, researchers observe subjects without manipulating the study environment. This type of study is useful in situations where controlled experiments may not be feasible or ethical, such as examining the effects of breast-feeding on mothers' bone mineral content.

Characteristics of observational studies include:
  • No manipulation: The researchers simply observe and record observations without intervention.
  • Presence of confounding variables: Other factors, not accounted for, may influence the results, possibly skewing the data.
  • Limited causal conclusions: It’s challenging to definitively link cause and effect because of the potential influence of confounding variables.
Despite the observational nature of the study, interesting associations or differences between groups can be identified, as in the case of BMC changes in breast-feeding women.
Causal Inference
Causal inference is the process of drawing a conclusion about a causal connection based on the conditions of the occurrence of an effect. In the context of this study on breast-feeding and bone mineral content, one might initially think that it demonstrates a causal relationship where breast-feeding causes loss in BMC. However, drawing such inferences requires careful consideration.

Reasons why causal inference is tricky in observational studies include:
  • Lack of randomization: Subjects are not randomly assigned, which can lead to selection bias.
  • Confounding factors: Other variables may influence both breast-feeding and BMC changes, creating a spurious association.
  • Observational limitations: The study can only highlight associations; it doesn't control factors as rigorously as randomized controlled trials (RCTs).
While causal inference is useful in generating hypotheses or directing further research, it’s important to interpret observational studies with caution to avoid overstating results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Paying for college College financial aid offices expect students to use summer eamings to help pay for college. But how large are these eamings? One large university studied this question by asking a random sample of 1296 students who had summer jobs how much they earned. The financial aid office separated the responses into two groups based on gender. Here are the data in summary form: \({ }^{30}\) $$ \begin{array}{lccc} \hline \text { Group } & n & \bar{\chi} & s_{\chi} \\ \text { Males } & 675 & \$ 1884.52 & \$ 1368.37 \\ \text { Females } & 621 & \$ 1360.39 & \$ 1037.46 \\ \hline \end{array} $$ (a) How can you tell from the summary statistics that the distribution of earnings in each group is strongly skewed to the right? The use of two-sample \(t\) procedures is still justified. Why? (b) Construct and interpret a \(90 \%\) confidence interval for the difference between the mean summer earnings of male and female students at this university. (c) Interpret the \(90 \%\) confidence level in the context of this study.

State which inference procedure from Chapter \(8,9,\) or 10 you would use. Be specific. For example, you might say, "Two-sample z test for the difference between two proportions." You do not need to carry out any procedures. Which inference method? (a) Drowning in bathtubs is a major cause of death in children less than 5 years old. A random sample of parents was asked many questions related to bathtub safety. Overall, \(85 \%\) of the sample said they used baby bathtubs for infants. Estimate the percent of all parents of young children who use baby bathtubs. (b) How seriously do people view speeding in comparison with other annoying behaviors? A large random sample of adults was asked to rate a number of behaviors on a scale of 1 (no problem at all) to 5 (very severe problem ). Do speeding drivers get a higher average rating than noisy neighbors? (c) You have data from interviews with a random sample of students who failed to graduate from a particular college in 7 years and also from a random sample of students who entered at the same time and did graduate. You will use these data to compare the percents of students from rural backgrounds among dropouts and graduates. (d) Do experienced computer game players earn higher scores when they play with someone present to cheer them on or when they play alone? Fifty teenagers with experience playing a particular computer game have volunteered for a study. We randomly assign 25 of them to play the game alone and the other 25 to play the game with a supporter present. Each player's score is recorded.

Prayer and pregnancy Two hundred women who were about to undergo IVF served as subjects in an experiment. Each subject was randomly assigned to either a treatment group or a control group. Women in the treatment group were intentionally prayed for by several people (called intercessors) who did not know them, a process known as intercessory prayer. The praying continued for three weeks following IVF. The intercessors did not pray for the women in the control group. Here are the results: 44 of the 88 women in the treatment group got pregnant, compared to 21 out of 81 in the control group. \({ }^{17}\) Is the pregnancy rate significantly higher for women who received intercessory prayer? To find out, researchers perform a test of \(H_{0}: p_{1}=p_{2}\) versus \(H_{a}: p_{1}>p_{2},\) where \(p_{1}\) and \(p_{2}\) are the actual pregnancy rates for women like those in the study who do and don't receive intercessory prayer, respectively. (a) Name the appropriate test and check that the conditions for carrying out this test are met. (b) The appropriate test from part (a) yields a \(P\) -value of 0.0007 . Interpret this \(P\) -value in context. (c) What conclusion should researchers draw at the \(\alpha=\) 0.05 significance level? Explain. (d) The women in the study did not know whether they were being prayed for. Explain why this is important.

Who talks more-men or women? Researchers equipped random samples of 56 male and 56 female students from a large university with a small device that secretly records sound for a random 30 seconds during each 12.5 -minute period over two days. Then they counted the number of words spoken by each subject during each recording period and, from this, estimated how many words per day each subject speaks. The female estimates had a mean of 16,177 words per day with a standard deviation of 7520 words per day. For the male estimates, the mean was 16,569 and the standard deviation was \(9108 .\) Do these data provide convincing evidence of a difference in the average number of words spoken in a day by male and female students at this university?

There are two common methods for measuring the concentration of a pollutant in fish tissue. Do the two methods differ, on average? You apply both methods to each fish in a random sample of 18 carp and use (a) the paired \(t\) test for \(\mu_{d}\) (b) the one-sample \(z\) test for \(p\). (c) the two-sample \(t\) test for \(\mu_{1}-\mu_{2}\). (d) the two-sample \(z\) test for \(p_{1}-p_{2}\). (e) none of these.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.