/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Steroids in high school \(A\) st... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Steroids in high school \(A\) study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois. Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids. Steroids, which are dangerous, are sometimes used in an attempt to improve athletic performance. \({ }^{13}\) Do the data give convincing evidence of a difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids? State appropriate hypotheses for a test to answer this question. Define any parameters you use..

Short Answer

Expert verified
Null Hypothesis: \( H_0: p_1 = p_2 \), Alternative Hypothesis: \( H_a: p_1 \neq p_2 \).

Step by step solution

01

Define Parameters

Let \( p_1 \) be the true proportion of Illinois high school freshmen who have used anabolic steroids, and let \( p_2 \) be the true proportion of Illinois high school seniors who have used anabolic steroids.
02

State Null Hypothesis

The null hypothesis \( H_0 \) states that there is no difference in the proportion of freshmen and seniors who have used anabolic steroids. Mathematically, this is \( H_0: p_1 = p_2 \).
03

State Alternative Hypothesis

The alternative hypothesis \( H_a \) asserts that there is a difference in the proportions. Mathematically, this is \( H_a: p_1 eq p_2 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Inference
Statistical inference is a process used to make predictions or decisions about a population based on sample data. It allows us to draw conclusions beyond the immediate data points available. In the context of hypothesis testing for steroids use among high school students, the study taps into statistical inference by examining proportions from samples to make assertions about larger groups.

To perform statistical inference, researchers often set up hypotheses. The null hypothesis (often denoted as \(H_0\)) represents the idea that there is no effect or difference, while the alternative hypothesis (denoted as \(H_a\)) suggests there is an effect or a difference. In the steroid use study, \(H_0\) assumes no difference in steroid use between freshmen and seniors, and \(H_a\) asserts a distinction in their usage rates.

Using statistical tools, we can test the likelihood of the observed data under the null hypothesis. If the data significantly deviate from what we expect under \(H_0\), we may choose to reject \(H_0\) in favor of \(H_a\). This forms the backbone of statistical inference, taking a leap from sample data to a broader insight about the population.
Proportion Comparison
Proportion comparison is a statistical method for determining whether two population proportions are identical or different. This involves comparing proportions from two or more groups—here, high school freshmen and seniors.

In hypothesis testing of proportions, we define two parameters: \( p_1 \) and \( p_2 \), which represent the true proportion of a characteristic (e.g., steroid use) in two distinct populations. For example, in our scenario, \( p_1 \) refers to freshmen, and \( p_2 \) to seniors.

The process involves:
  • Calculating sample proportions from the survey data, which is \( \hat{p}_1 = \frac{34}{1679} \) for freshmen and \( \hat{p}_2 = \frac{24}{1366} \) for seniors.
  • Testing the null hypothesis \(H_0: p_1 = p_2\) against the alternative \(H_a: p_1 eq p_2\).
The analysis tools, like the Z-test or chi-square test, evaluate whether differences in sample proportions suggest a significant difference in population proportions. This approach helps in determining whether any observed discrepancies are statistically significant or just due to random sample variation.
Survey Data Analysis
Survey data analysis is crucial for extracting meaningful information from gathered data. In the study on steroids, analyzing survey data helps to draw insights about steroid usage trends among different student groups. The focus is to interpret the dataset meaningfully.

Key steps in survey data analysis include:
  • Organizing data into a useable format—the proportions of students who have used steroids are calculated for freshmen and seniors.
  • Using statistical techniques to study relationships or differences between groups. In this case, hypothesis testing is the technique used to examine whether freshmen and seniors differ in their steroid usage.
  • Interpreting findings in a way that informs decision-making or further actions.
For accurate survey data analysis, it's essential to ensure that the chosen sample accurately represents the population. Sampling random high school freshmen and seniors ensures the findings can generalize to the broader population of Illinois high school students.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How tall? The heights of young men follow a Normal distribution with mean 69.3 inches and standard deviation 2.8 inches. The heights of young women follow a Normal distribution with mean 64.5 inches and standard deviation 2.5 inches. Suppose we select independent SRSs of 16 young men and 9 young women and calculate the sample mean heights \(\bar{x}_{M}\) and \(\bar{x}_{W}\). (a) What is the shape of the sampling distribution of \(\bar{x}_{M}-\bar{x}_{W} ?\) Why? (b) Find the mean of the sampling distribution. Show your work. (c) Find the standard deviation of the sampling distribution. Show your work.

Prayer and pregnancy Two hundred women who were about to undergo IVF served as subjects in an experiment. Each subject was randomly assigned to either a treatment group or a control group. Women in the treatment group were intentionally prayed for by several people (called intercessors) who did not know them, a process known as intercessory prayer. The praying continued for three weeks following IVF. The intercessors did not pray for the women in the control group. Here are the results: 44 of the 88 women in the treatment group got pregnant, compared to 21 out of 81 in the control group. \({ }^{17}\) Is the pregnancy rate significantly higher for women who received intercessory prayer? To find out, researchers perform a test of \(H_{0}: p_{1}=p_{2}\) versus \(H_{a}: p_{1}>p_{2},\) where \(p_{1}\) and \(p_{2}\) are the actual pregnancy rates for women like those in the study who do and don't receive intercessory prayer, respectively. (a) Name the appropriate test and check that the conditions for carrying out this test are met. (b) The appropriate test from part (a) yields a \(P\) -value of 0.0007 . Interpret this \(P\) -value in context. (c) What conclusion should researchers draw at the \(\alpha=\) 0.05 significance level? Explain. (d) The women in the study did not know whether they were being prayed for. Explain why this is important.

Who tweets? Do younger people use Twitter more often than older people? In a random sample of 316 adult Internet users aged 18 to \(29,26 \%\) used Twitter. In a separate random sample of 532 adult Internet users aged 30 to \(49,14 \%\) used Twitter. \({ }\) (a) Calculate the standard error of the sampling distribution of the difference in the sample proportions (younger adults - older adults). What information does this value provide? (b) Construct and interpret a \(90 \%\) confidence interval for the difference between the true proportions of adult Internet users in these age groups who use Twitter.

Cholesterol The level of cholesterol in the blood for all men aged 20 to 34 follows a Normal distribution with mean 188 milligrams per deciliter \((\mathrm{mg} / \mathrm{dl})\) and standard deviation \(41 \mathrm{mg} / \mathrm{dl}\). For 14 -year-old boys, blood cholesterol levels follow a Normal distribution with mean \(170 \mathrm{mg} / \mathrm{dl}\) and standard deviation \(30 \mathrm{mg} / \mathrm{dl}\). Suppose we select independent SRSs of \(25 \mathrm{men}\) aged 20 to 34 and 36 boys aged 14 and calculate the sample mean cholesterol levels \(\bar{x}_{M}\) and \(\bar{x}_{B}\) (a) What is the shape of the sampling distribution of \(\bar{x}_{M}-\bar{x}_{B} ?\) Why? (b) Find the mean of the sampling distribution. Show your work. (c) Find the standard deviation of the sampling distribution. Show your work.

Who owns iPods? As part of the Pew Internet and American Life Project, researchers surveyed a random sample of 800 teens and a separate random sample of 400 young adults. For the teens, \(79 \%\) said that they own an iPod or MP3 player. For the young adults, this figure was \(67 \%\). Do the data give convincing evidence of a difference in the proportions of all teens and young adults who would say that they own an iPod or MP3 player? State appropriate hypotheses for a test to answer this question. Define any parameters you use.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.