91Ó°ÊÓ

Given in the question that, The P-value for a one-sided test of the null hypothesis $H_0:\mathrm{μ}=15$is $0.03$.

We need to flnd that Whether the $99\%$confldence interval for $\mathrm{μ}$include $15$.

$P$-value is $0.03$

Confidence level $=99\%$

Reject the null hypothesis, if$P-$value is less than the significance level.

The level of significance is:

Level of significance$\left(\mathrm{Î\pm }\right)=1-$Confidence level

$=1-0.99$

$=0.01$

The null and alternative hypotheses are:

$H_0:\mathrm{μ}=15$

$H_a:\mathrm{μ}≠15$

Here $P$-value $(0.03)>\mathrm{Î\pm }(0.01)$. The null hypothesis is not rejected. Thus, it could be said that the confidence level would contain$15.$

Given in the question that, The $P$-value for a one-sided test of the null hypothesis $H_0:\mathrm{μ}=15$is $0.03$.

We need to flnd that Whether the$95\%$confldence interval for $\mathrm{μ}$include

$15$.

Confidence level $=95\%$

Reject the null hypothesis, if $\mathrm{P}$-value is less than the significance level.

The level of significance is:

Level of significance $\left(\mathrm{Î\pm }\right)=1$- Confidence level

$=1-0.95$

$=0.05$

The null and alternative hypotheses are:

$H_0:\mathrm{μ}=15$

$H_a:\mathrm{μ}≠15$

Here $\mathrm{P}$-value$(0.03)<\mathrm{Î\pm }(0.05)$. The null hypothesis is rejected. Thus, it could not be said that the confidence level would contain$15$.