91Ó°ÊÓ

The scientific strategy requires that one can test it. Scientists for the most part base scientific speculations on previous observations that can't satisfactorily be explained with the available scientific theories

The hypotheses are,

$\begin{array}{r}{H}_0:\mathrm{μ}=64\\ H_a:\mathrm{μ}≠64\end{array}$

calculating the degree of freedom,

$$\begin{gathered} Df=n−1 \\ =25-1=24 \end{gathered}$$

Using a calculator the p-value is found to be$0.136$

For the two-sided test p-value is=$2×0.1369=0.2738$

localid="1654666340202" $⇒0.2738>(\mathrm{Î\pm }=0.01\text{and}\mathrm{Î\pm }=0.05)$

Hence the p-value is $0.2738$and as it is greater than the significance levels the null hypothesis is not rejected.

The hypotheses,

$\begin{array}{r}{H}_0:\mathrm{μ}=64\\ H_a:\mathrm{μ}<64\end{array}$

Calculating the p-value for one-tailed test,

localid="1654666370875" $$\begin{gathered} =P(t\&²\mu ³Ù;âˆ\pounds t|) \\ =P(t>|−1.12|)=0.1369 \end{gathered}$$

Hence the p-value is $0.1369$and as it is greater than the significance levels the null hypothesis is not rejected.