91Ó°ÊÓ

Given in the question, the slot player receives at least one apple for each lever pull. We have to calculate the probability.

$P\left(Atleast1apple\right)=1-P\left(noapple\right)$

Obtain the probability that the slot player gets at least one apple in one pull of the lever:

It is given that, a slot machine has $5$wheels, and each wheel has $5$symbols (apple, grape, peach, pear, and plum).

The wheel spins independently and the five symbols are equally likely to appear.

The probability that the slot player gets at least one apple in one pull of the lever is obtained as$0.67232$from the calculation given below:

$P\left(Atleast1apple\right)=1-\left(noapple\right)$

$=1-\left(noappleon5wheels\right)$

$=1-\left[P\left(noappleon1stwheel\right)×...×P\left(noappleon5thwheel\right)\right]$

$=1-\left[\frac{4}{5}×\frac{4}{5}×\frac{4}{5}×\frac{4}{5}×\frac{4}{5}\right]$

=0.67232

Therefore The probability that the slot player gets at least one apple in one pull of the lever is$0.67232$

Given in the question that,in the readers view the lever was pulled 5 times we have to find the probability.

$P\left(atleast1apple\right)=1-P\left(noapple\right)$

In the readers view, the lever was pulled$5$times.

The reader's question is to compute the probability of getting at least one apple in five pulls of the lever.

The probability that the slot player gets at least one apple in five pulls of the lever is obtained as$0.996222$from the calculation given below:

$P(Atleast1apple)=1-P\left(noapple\right)$

$=1-P\left[\left(Noappleson5wheelsforallthe5pulls\right)\right]$

$=1-\left[P\left(noappleon1stwheel\right)×...×P\left(noappleon5thapple\right)\right]$

$=1-{\left[\frac{4}{5}×\frac{4}{5}×\frac{4}{5}×\frac{4}{5}×\frac{4}{5}\right]}^5$

localid="1649260955127" $=1-0.003778$

$=0.996222$

The probability that the slot player gets at least one apple in five pulls of the lever is$0.996222$