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Heat through the glass How well materials conduct heat matters when designing houses, for example. Conductivity is measured in terms of watts of heat power transmitted per square meter of surface per degree Celsius of temperature difference on the two sides of the material. In these units, glass has conductivity about 1. The National Institute of Standards and Technology provides exact data on properties of materials. Here are measurements of the heat conductivity of 11randomly selected pieces of a particular type of glass:

1.111.071.111.071.121.081.081.181.181.181.12

Is there convincing evidence that the conductivity of this type of glass is greater than 1? Carry out a test to help you answer this question.

Short Answer

Expert verified

There is no convincing evidence that the conductivity of this type of glass is greater than 1.

Step by step solution

01

Given information

The National Institute of Standards and Technology provides exact data on properties of materials. Here are measurements of the heat conductivity of 11randomly selected pieces of a particular type of glass:

1.111.071.111.071.121.081.081.181.181.181.12

02

Explanation

State: H0:μ=1versusHa:μ>1, where μis the actual mean amount of thermal conductivity

Plan: One-sample t test for μ.

Random: The sample was randomly selected.

Normal: Previous experience tells us that thermal conductivity will be close to Normal. Independent: There are at least 11selected glasses.

Do: t=9.95, P-value=0.

Conclude: Since our P-value is less than 0.05, we reject H0.

There is no convincing evidence that the conductivity of this type of glass is greater than1.

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Most popular questions from this chapter

One-sided test Suppose you carry out a significance test of H0:μ=5versus Ha:μ>5based on a sample of size n=20and obtain t=1.81.

(a) Find the P-value for this test using (i) Table Band (ii) your calculator. What conclusion would you draw at the 5%significance level? At the 1%significance level?

(b) Redo part (a) using an alternative hypothesis ofHa:μ≠5.

Bullies in middle school A University of Illinois study on aggressive behavior surveyed a random sample of 558 middle school students. When asked to describe their behavior in the last 30 days, 445 students said their behavior included physical aggression, social ridicule, teasing, name-calling, and issuing threats. This behavior was not defined as bullying in the questionnaire. Is this evidence that more than three-quarters of the students at that middle school engage in bullying behavior? To find out, Maurice decides to perform a significance test. Unfortunately, he made a few errors along the way. Your job is to spot the mistakes and correct them.

H0:p=0.75Ha:p->0.797

where p= the true mean proportion of middle school students who engaged in bullying.

- A random sample of 558 middle school students was surveyed.

- 558(0.797)=444.73 is at least 10.

z=0.75−0.7970.797(0.203)445=−2.46;P-value=2(0.0069)=0.0138

The probability that the null hypothesis is true is only 0.0138, so we reject H0. This proves that more than three-quarters of the school engaged in bullying behavior.

Spinning for apples (6,3 or 7.3) In the "Ask Marilyn" column of Parade magzine, a reader posed this question: "Say that a slot machine has five wheels, and each wheel has five symbols: an apple, a grape, a peach, a pear, and a plum. I pull the lever five times. What are the chances that I'll get at least one apple?" Suppose that the wheels spin independently and that the fre symbols are equally likely to appear on each wheel in a given spin.

(a) Find the probability that the slot player gets at least one apple in one pull of the lever. Show your method clearly.

(b) Now answer the reader's question. Show your method clearly.

After once again losing a football game to the archrival, a college’s alumni association conducted a survey to see if alumni were in favor of firing the

coach. An SRS of 100 alumni from the population of all living alumni was taken, and 64 of the alumni in the sample were in favor of firing the coach.

Suppose you wish to see if a majority of living alumni are in favor of firing the coach. The appropriate test statistic is

a. z=0.64-0.50.64(0.36)100

b.t=0.64-0.50.64(0.36)100

c.z=0.64-0.50.5(0.5)100

d.z=0.64-0.50.64(0.36)64

e.z=0.5-0.640.5(0.5)100

You read that a statistical test at significance levelα=0.05 has power 0.78. What are the probabilities of Type I and Type II errors for this test?

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