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T6.8. Seventeen people have been exposed to a particular disease. Each one independently has a 40%chance of contracting the disease. A hospital has the capacity to handle10 cases of the disease. What is the probability that the hospital鈥檚 capacity will be exceeded?
(a) 0.011(b) 0.035(c) 0.092(d) 0.965(e) 0.989

Short Answer

Expert verified

The probability of the hospital's capacity will be exceeded is 0.035. So, the option (b) is correct.

Step by step solution

01

Given information

A hospital has the capacity to handle 10 cases of the disease. Each one independently has a 40% chance of contracting the disease.

02

Explanation

Let, Sample size n=17
Probability of success p=40%=0.40
Definition binomial probability:
P(X=k)=nkpk(1-p)n-k
Evaluate k=11,12,13,14,15,16,17:

P(X=11)=17110.4011(10.40)17110.0242

P(X=12)=17120.4012(10.40)17120.0081

P(X=13)=17130.4013(10.40)17130.0021

P(X=14)=17140.4014(10.40)17140.0004

P(X=15)=17150.4015(10.40)17150.0001

P(X=16)=17160.4016(10.40)17160.0000

P(X=17)=17170.4017(10.40)17170.0000

Then, the probabilities as:

=P(X=11)+P(X=12)+P(X=13)+.........+P(X=16)+P(X=17)

=0.0242+0.0081+0.0021+0.0004+0.0001+0.0000+0.0000

=0.03480.035

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