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78. Rhubarb Refer to Exercise 76. Would you be surprised if 3 or more of the plants in the bundle die before producing any rhubarb? Calculate an appropriate probability to support your answer.

Short Answer

Expert verified

The probability is less than 5%,ThereforeP(X3)=1.16%and the result is surprising.

Step by step solution

01

Given information

Three or more of the plants in the bundle die before producing any rhubarb.

02

Explanation

Given, n=10and p=0.05

The Binomial Probability:

P(X=k)=nkpk(1p)nk

P(X=0)=100(0.05)0(0.95)1000.5987

P(X=1)=101(0.05)1(0.95)1010.315

P(X=2)=102(0.05)2(0.95)1020.0746

P(X3)=1P(X=0)P(X=1)P(X=2)=10.59870.31510.0746=0.0116=1.16%

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