91影视

Given in the question that, Consider $X$as a number between $0$and $1$created by a random number generator.

We have to And to find the probability for $P(X>0.49)$.

The variable$X$ has the uniform distribution.
Therefore, the value of $P(X>0.49)$by:

$$\begin{gathered} P(X>0.49)=(1鈭�0.49)脳1 \\ =0.51 \end{gathered}$$

Let $X$be a number between $0$and $1$produced by a random number generator.

We have to find the probability for $P(X鈮�0.49)$.

The variable $X$has the uniform distribution.

Therefore, the value of $P(X鈮�0.49)$will be:

$$\begin{gathered} P(X鈮�0.49)=(1-0.49)脳1 \\ =0.51 \end{gathered}$$

Let $X$be a number between $0$and $1$ produced by a random number generator.

We have to find the probability for $P(0.19鈮�X<0.37or0.84<X鈮�1.27)$.

Since, the probability for$P(0.19鈮�X<0.37or0.84<X鈮�1.27)$can determine as:
$$\begin{gathered} P(0.19鈮�X<0.37)=(0.37-0.19)脳1 \\ =0.18 \end{gathered}$$
$$\begin{gathered} P(0.84<X鈮�1.27)=(1-0.84)脳1 \\ =0.16 \end{gathered}$$

Then,

$$\begin{gathered} P(0.19鈮�X<0.37)=0.18+0.16 \\ =0.34 \\ or \\ P(0.84<X鈮�1.27)=0.18+0.16 \\ =0.34 \end{gathered}$$