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At least one of Ashley's children is suffering from the disease.

Condition probability: $P\left(A\right|B)=\frac{P(AandB)}{P\left(B\right)}$

Use the following formula to calculate the probability of a condition:

$P\left(A\right|B)=\frac{P(AandB)}{P\left(B\right)}$

$P(Twoboys)=\frac{favourableoutcomes}{possibleoutcomes}=\frac{1}{4}$$=0.25$

$P(Atleastoneboy)=\frac{favourableoutcomes}{possibleoutcomes}=\frac{3}{4}=0.75$

As a result, the conditional probability is:

$P(Twoboy||Atleastoneboy)=\frac{P(Twoboys)}{P(Atleastoneboy)}=\frac{0.25}{0.75}=\frac{1}{3}鈮�0.3333=33.33\%$

As a result, the chances of her having two sons are $33.33\%$

Condition probability: $P(A/B)=\frac{P(AandB)}{P\left(B\right)}$

$P(Twoboys)=\frac{favourableoutcomes}{possibleoutcomes}=\frac{1}{4}=0.25$

$P(oldestisboy)=\frac{favourableoutcomes}{possibleoutcomes}=\frac{2}{4}=0.50$

As a result, the conditional probability is: $P(Twoboy||Atleastoneboy)=\frac{P(Twoboys)}{P(Atleastoneboy)}=\frac{0.25}{0.50}=0.50$

As a result, the conditional chance of her having two sons is $0.50$