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For the study of Jordanian children in Exercise 64, the sample mean hemoglobin level was 11.3 mg/dl and the sample standard deviation was 1.6 mg/dl.

(a) Calculate the test statistic.

(b) Find the P-value using Table B. Then obtain a more precise P-value from your calculator.

Short Answer

Expert verified

a. the test statistic is-3.094

b. the P-value using Table B 0.016

Step by step solution

01

Introduction

A p-value estimates the probability of obtaining the noticed outcomes, it is consistent with expectations that the invalid hypothesis. The lower the p-esteem, the more prominent the statistical significance of the noticed difference

02

Explanation Part (a)

The sample mean is x-=11.3

The sample size is n = 50

Standard deviation is 1.6

Using,

localid="1652954330667" t=x-−μsn

localid="1663929363504" =11.3−121.650=-3.094

Hence the test statistic islocalid="1663929380848" -3.094

03

Explanation Part (b)

Calculating the degree of freedom,

n-1=50-1=49

The p-value is,

=Ptc>|−3.094|=0.0016

Hence the P-value is0.0016

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