/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 12 Foresters are interested in pred... [FREE SOLUTION] | 91影视

91影视

Foresters are interested in predicting the amount of usable lumber they can harvest from various tree species. They collect data on the diameter at breast height (DBH) in inches and the yield in board feet of a random sample of 20Ponderosa pine trees that have been harvested. (Note that a board foot is defined as a piece of lumber 12inches by 12inches by 1inch.) A scatterplot of the data is shown below

(a) Some computer output and a residual plot from a least squares regression on these data appear below. Explain why a linear model may not be appropriate in this case.

(B) Use both models to predict the amount of usable lumber from a Ponderosa pine with diameter 30inches. Show your work.

(c) Which of the predictions in part (b) seems more reliable? Give appropriate evidence to support your choice.

Short Answer

Expert verified

a). A linear model is not ideal there are curvature is residual plot.

b). The regression line is option 1. y^=117.0899and option 2. y^=102.967.

c) The predictions in part (b) seems more reliable are option 1: y^=117.0899.

Step by step solution

01

Part (a) Step 1:  Given information

A scatterplot of the data is shown below,

02

Part (a) Step 2: Explanation

If a linear model is adequate, the histogram should be about normal, and the residuals scatterplot should indicate random scatter. The linear model is not appropriate if the residual plot shows a curved relationship.

03

Part (b) Step 1: Given Information 

The using all models to estimate the volume of available pine lumber 30 inches in diameter from a ponderosa pine.

04

Part (b) Step 2: Explanation 

Option 1: Regression line of least square,

y^=a+bx

The coefficients aand b are:

a=2.078and

b=0.0042597

Then the regression line of least square is:

y^=2.078+0.0042597x3

With x=DBHand ythe yield

Putting the Xby30:

y^=2.078+0.0042597(30)3

=117.0899.

05

Part (b) Step 3: Explanation 

Option 2: Regression line is y^=a+bx

The coefficients aand bare a=1.2319and

b=0.113417

Then the regression line of least square is

y^=a+bx

The coefficients aand barea=1.2319

b=0.113417

Then the regression line of least-squares becomes:

With x=DBH and ythe yield.

Puttingxby 30: y^=102.967.

06

Part (c) Step 1: Given Information 

The prediction that is looks more reliable in part (b).

07

Part (c) Step 2: Explanation 

From the part (b)

Option 1: y^=117.0899

Option 2: y^=102.967

Option 1 provides a more accurate estimate because its residual plot shows no discernible trend, but Option 2's residual plot shows a discernible curve.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ecologists look at data to learn about nature鈥檚 patterns. One pattern they have found relates the size of a carnivore (body mass in kilograms) to how many of those carnivores there are in an area. The right measure of 鈥渉ow many鈥 is to count carnivores per 10,000kilograms (kg) of their prey in the area. The table below gives data for 25carnivore species

Carnivore speciesBody mass(kg)Abundance(per 10,000 kg of prey)Least weasel0.141656.49Ermine0.16406.66Small Indian mongoose0.55514.84Pine marten1.331.84Kit fox2.0215.96Channel Island fox2.16145.94Arctic fox3.1921.63Red fox4.632.21Bobcat10.09.75Canadian lynx11.24.79European badger13.07.35Coyote13.011.65Ethiopian wolf14.52.70Eurasian lynx20.00.46Wild dog25.01.61Dhole25.00.81Snow leopard40.01.89Wolf46.00.62Leopard46.56.17Cheetah50.02.29Puma51.90.94Spotted hyena58.60.68Tiger182.03.40Polar bear310.00.33

Here is a scatterplot of the data.

(a) The following graphs show the results of two different transformations of the data. Would an exponential model or a power model provide a better description of the relationship between body mass and abundance? Justify your answer.

(b) Minitab output from a linear regression analysis on the transformed data of log(abundance) versus log(body mass) is shown below. Give the equation of the least-squares regression line. Be sure to define any variables you use.

PredictorCoefSE CoefTPConstant1.95030.134214.530.000log(body-1.048110.09802-10.690.000mass)

S=0.423352R-Sq=83.3%R-Sq(adj)=82.5%

(c) Use your model from part (b) to predict the abundance of black bears, which have a body mass of 92.5kilograms. Show your work.

(d) A residual plot for the linear regression in part (b) is shown below. Explain what this graph tells you about how well the model fits the data.

Is wine good for your heart? A researcher from the University of California, San Diego, collected data on average per capita wine consumption and heart disease death rate in a random sample of 19 countries for which data were available. The following table displays the data.

(a) Is there statistically significant evidence of a negative linear relationship between wine consumption and heart disease deaths in the population of countries? Carry out an appropriate significance test at the =0.05level.

(b) Calculate and interpret a 95% confidence interval for the slope of the population regression line.

Does how long young children remain at the lunch table help predict how much they eat? Here are data on a random sample of 20toddlers observed over several months. 鈥淭ime鈥 is the average number of minutes a child spent at the table when lunch was served. 鈥淐alories鈥 is the average number of calories the child consumed during lunch, calculated from careful observation of what the child ate each day.

(a) A scatterplot of the data with the least-squares line added is shown below. Describe what this graph tells you about the relationship between these two variables.

Minitab output from a linear regression on these data is shown below.

PredictorCoefSE CoefTPConstant560.6529.3719.090.000Time-3.07710.8498-3.620.002S=23.3980R-Sq=42.1%R-Sq(adj)=38.9%

(b) What is the equation of the least-squares regression line for predicting calories consumed from the time at the table? Define any variables you use.

(c) Interpret the slope of the regression line in context. Does it make sense to interpret the intercept in this case? Why or why not?

(d) Do these data provide convincing evidence of a negative linear relationship between time at the table and calories consumed in the population of toddlers? Carry out an appropriate test at the A =0.01level to help answer this question.

In the casting of metal parts, molten metal flows through a 鈥済ate鈥 into a die that shapes the part. The gate velocity (the speed at which metal is forced through the gate) plays a critical role in die casting. A firm that casts cylindrical aluminium pistons examined a random sample of 12pistons formed from the same alloy of metal. What is the relationship between the cylinder wall thickness (inches) and the gate velocity (feet per second) chosen by the skilled workers who do the casting? If there is a clear pattern, it can be used to direct new workers or to automate the process. A scatterplot of the data is shown below

A least-squares regression analysis was performed on the data. Some computer output and a residual plot are shown below. A Normal probability plot of the residuals (not shown) is roughly linear.

Do these data provide convincing evidence of a straight-line relationship between thickness and gate velocity in the population of pistons formed from this alloy of metal? Carry out an appropriate significance test at the =0.05level.

Expose marine bacteria to X-rays for time periods from 1to 15minutes. Here are the number of surviving bacteria (in hundreds) on a culture plate after each exposure time.

TimetCountyTimetCounty1355956221110383197113641661232514213216106141971041515860

(a) Make a reasonably accurate scatterplot of the data by hand, using time as the explanatory variable. Describe what you see.

(b) A scatterplot of the natural logarithm of the number of surviving bacteria versus time is shown below. Based on this graph, explain why it would be reasonable to use an exponential model to describe the relationship between the count of bacteria and time.

Minitab output from a linear regression analysis on the transformed data is shown below.

PredictorCoefSE CoefTPConstant5.973160.0597899.920.000Time-0.2184250.006575-33.220.000

S=0.110016R-Sq=98.8%R-Sq(adj)=98.7%

Give the equation of the least-squares regression line. Be sure to define any variables you use.

(d) Use your model to predict the number of surviving bacteria after 17minutes. Show your work. Do you expect this prediction to be too high, too low, or about right? Explain

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.