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Park rangers are interested in estimating the weight

of the bears that inhabit their state. The rangers have data

on weight (in pounds) and neck girth (distance around

the neck in inches) for 10 randomly selected bears. Some

regression output for these data is shown below.

A bear was recently captured whose neck girth was 35inchesand whose weight was 466.35pounds. If this bear were added to the data set given above, what would be the effect on the value ofr2?

(a) It would decrease the value of r2because the added

point is an outlier.

(b) It would increase the value of r2because any point

added to the data would increase the percent of variation

in bear weight that can be explained by the least-squares

regression line.

(c) It would increase the value of r2because the added

point lies on the least-squares regression line and is far from

the point (x,y)

(d) It would have no effect on the value ofr2 because the

added point lies far from the point (x,y)

(e) It would have no effect on the value of r2because it lies

on the least-squares regression line.

Short Answer

Expert verified

The option (b) It would increase the value of r2because any point added to the data would increase the percent of variation in bear weight that can be explained by the least-squares regression line is correct .

Step by step solution

01

Given information

We are given that A bear was recently captured whose neck girth was 35inchesand whose weight was 466.35pounds. If this bear were added to the data set given above, what would be the effect on the value of r2?

we need to find that what would be the effect on the value of r2?

02

Explanation

We note that if we would add the bear with neck girth 35inchesand weight 466.35 pounds to the scatterplot . moreover , this plot will lie in the extension of Least square regression line and thus will lie on least square regression line.

Moreover, standard error of estimation s will then also decrease ,because the Added data will have a prefer prediction . Thus our predictions are more accurate Resulting in less variations and thus a lower standard error of the estimation s.

so option (b) It would increase the value of r2because any point added to the data would increase the percent of variation in bear weight that can be explained by the least-squares regression line is correct .

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