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Standard Normal areas Use Table A to find the proportion of observations from a standard Normal distribution that falls in each of the following regions. In each case, sketch a standard Normal curve and shade the area representing the region.

(a)z2.25

(c)z>1.77

(b)z2.25

(d) 2.25<z<1.77

Use the standard Normal distribution to determine a z-score from a percentile.

Short Answer

Expert verified

a) As a result, 12.2percent of observations are in the z2.25area.

b) The observation percentage is 0.9878.

c) As a result, 3.84percent of observations are more than 1.77.

d) As a result, 94.94percent of observations are in the range of -2.25to 1.77.

Step by step solution

01

Part(a) Step 1: Given Information

Given that the question is:

z2.25

02

Part(a) Step 2: Explanation

In the graph below, the given region is shown as follows:

The number below -2.25 is 0.0122, according to the conventional normal table.

03

Part(b) Step 1: Given Information

Given that the question is:

z2.25

04

Part(b) Step 2: Explanation

The region in question is seen in the graph below.

Part (a) shows that the region below -2.25is 0.0122.

The fraction of observations greater than -2.25is then computed.

=Total Proportion-proportion of observations before -2.25

=1-0.0122=0.9878

05

Part(c) Step 1: Given Information

Given that the question is:

z>1.77

06

Part(c) Step 2: Explanation

The region in question is seen in the graph below.

The area before 1.77is 0.9616using Standard Normal tables. As a result, 0.9616is the fraction of observations below 1.77.

The proportion of observations larger than 1.77is then calculated by subtracting the value of the proportion less than 1.77from 1(total proportion).

1-0.9616=0.0384=3.84%

07

Part(d) Step 1: Given Information

Given that the question is:

2.25<z<1.77

08

Part(d) Step 2: Explanation

The region in question is seen in the graph below.

Subtract the area before -2.25from the area before 1.77to get the needed region.

The area before -2.25is 0.0122, as calculated from component (a). Also, 0.9616is the region preceding 1.77. (from Standard Normal tables)

Then there's the region between -2.25and 1.77.

0.9616-0.0122=0.9494=94.94%

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