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Software gives test statistic ${蠂}^2=69.8$ and $P$ value close to $0$.

The p-value is the probability of obtaining a value (statistic) of the test result as extreme as, or more extreme than, the value that has been obtained, assuming ${\mathrm{H}}_0$to be true. So, the p-value is not considered in making the probability. It is just a probability of getting a certain result when ${\mathrm{H}}_0$is true.

In the given scenario, the interpretation of the result is:

The probability of obtaining a test statistic value $X^2=69.8$at least as extreme as the observed value, when the null hypothesis is assumed to be true is$0$.

That is, the probability of getting a random sample of $4877$teens that yields a value of localid="1650450318348" $x^2$of localid="1650450326474" $69.8$or larger iflocalid="1650450369804" ${\mathrm{H}}_0$is true is basically true.

Therefore, the correct answer is Option (b).