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51. You want to design a study to estimate the proportion of students at your school who agree with the statement, 鈥淭he student government is an effective organization for expressing the needs of students to the administration.鈥 You will use a 95% confidence interval, and you would like the margin of error to be 0.05 or less. The minimum sample size required is
(a) 22. (b) 271. (c) 385. (d) 769. (e) 1795.

Short Answer

Expert verified

The correct answer is option (c) 385.

Step by step solution

01

Given information

To find the minimum sample size required for 95%confidence interval, and the margin of error to be 0.05 or less.

02

Explanation

Let, mirror of error is E=0.05.

Determine the sample size as:

p^unknown: n=z/220.25E2

Using table A, for confidence level 95%,
z/2=1.96
p^ is unknown, then the sample size is:
n=z/220.25E2

=1.9620.250.052

385

As a result, option (c) 385 is correct.

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Most popular questions from this chapter

A radio talk show host with a large audience is interested in the proportion pof adults in his listening area who think the drinking age should be lowered to eighteen. To find this out, he poses the following question to his listeners: "Do you think that the drinking age should be reduced to eighteen in light of the fact that eighteen-year-olds are eligible for military service?" He asks listeners to phone in and vote "Yes" if they agree the drinking age should be lowered and "No" if not. Of the 100people who phoned in, 70answered "Yes." Which of the following conditions for inference about a proportion using a confidence interval are violated?

I. The data are a random sample from the population of interest.

II. nis so large that both npandn1-pare at least 10.

III. The population is at least 10times as large as the sample.

(a) I only

(c) III only

(c) I, II, and III

(b) II only

(d) I and II only

Abstain from drinking In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students were classified as abstainers (nondrinkers).

(a) Construct and interpret a 99% confidence interval forp. Follow the four-step process.

(b) A newspaper article claims that 25% of U.S. college students are nondrinkers. Use your result from (a) to comment on this claim.

Going to the prom Tonya wants to estimate what proportion of the seniors in her school plan to attend the prom. She interviews an SRS of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom

93% confidence Find z*fora93%confidence interval using Table A or your calculator. Show your method.

Refer to Exercise 12. As Gallup indicates, the 3percentage point margin of error for this poll includes only sampling variability (what they call 鈥渟ampling error鈥). What other potential sources of error (Gallup calls these 鈥渘on-sampling errors鈥) could affect the accuracy of the59% estimate?

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