91Ó°ÊÓ

The given data is

From the given data

On the horizontal axis, we plotted mass (the explanatory variable) and metabolic rate (the response variable).

The finished scatterplot for the given data is shown below.

The given data is

The least-squares regression line's equation using the MINITAB is,

The regression line is$\hat{Y}=197+24.1X$

Look at the scatter figure above with the regression line added.

The given data is

The equation of the least-squares regression line is $\hat{Y}=197+24.1X$

The rate at which the anticipated response $Y$moves among the line as the explanatory variable $X$changes is represented by the slope b of the aforementioned regression line $\left(197\right)$. $b$is the expected change in Y when $X$is increased by one unit. If mass increases by one unit, metabolic rate increases by $24.1cal/24hrs$, as shown in $b$.

The given data is

The equation of the least-squares regression line, $\hat{Y}=197+24.1X$

For, the predicted value of $Y$is

$\hat{Y}=197+24.1X$

$$\begin{gathered} =197+24.1×45 \\ =1281.5 \end{gathered}$$

This indicates that the expected metabolic rate for a lady with a body mass of $45kg$is $1281.5$calories per $24$hours.